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DIA [1.3K]
4 years ago
6

What is the expanded form of 3×(x+3)^2

Mathematics
1 answer:
saul85 [17]4 years ago
7 0
3x(x+3)^2
3x(x^2 + 6x + 9)
= 3x^3 + 18x^2 + 27x

answer
3x^3 + 18x^2 + 27x
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Inessa05 [86]

Step-by-step explanation:

f(-5)=-10+15=5

g(5)=25-1=24

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Help please I need to answer this question
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Answer:

D

Step-by-step explanation:

first find the perimeter of both triangles

Original perimeter: 72 in

scaled perimeter: 24 in

A is wrong since the scaled perimeter is actually smaller.

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Answer:

90% confidence interval for the difference between the two population means

( -23.4166 , -6.5834)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given first sample size n₁ = 100

Given mean of the first sample x₁⁻ = 178

Standard deviation of the sample S₁ = 35

Given second sample size n₂= 100

Given mean of the second sample x₂⁻ = 193

Standard deviation of the sample S₂ = 37

<u><em>Step(ii):-</em></u>

Standard error of two population means

        se(x^{-} _{1} -x^{-} _{2} ) = \sqrt{\frac{s^{2} _{1} }{n_{1} }+\frac{s^{2} _{2} }{n_{2} }  }

       se(x^{-} _{1} -x^{-} _{2} ) = \sqrt{\frac{(35)^{2}  }{100 }+\frac{(37)^{2}  }{100 }  }

        se(x^{-} _{1} -x^{-} _{2} ) =  5.093

Degrees of freedom

ν  = n₁ +n₂ -2 = 100 +100 -2 = 198

t₀.₁₀ = 1.6526

<u><em>Step(iii):-</em></u>

<u><em> 90% confidence interval for the difference between the two population means</em></u>

<u><em></em></u>(x^{-} _{1} - x^{-} _{2} - t_{\frac{\alpha }{2} }  Se (x^{-} _{1} - x^{-} _{2}) , x^{-} _{1} - x^{-} _{2} + t_{\frac{\alpha }{2} }  Se (x^{-} _{1} - x^{-} _{2})<u><em></em></u>

(178-193 - 1.6526 (5.093) , 178-193 + 1.6526 (5.093)

(-15-8.4166 , -15 + 8.4166)

( -23.4166 , -6.5834)

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I NEED A BIT MORE DETAIL LOL

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Answer:

Its A!

Step-by-step explanation:

i took the test on edge 2020-2021

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