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Anastasy [175]
3 years ago
13

Solve equation for g=

Mathematics
1 answer:
harina [27]3 years ago
6 0

Answer: g= -2

I hope this helps you



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Solve 10e^2x - 5 =23^x for x.
yawa3891 [41]

10e^{2x}-5=23e^x\qquad\text{subtract}\ 23e^x\ \text{from both sides}\\\\10e^{2x}-23e^x-5=0\\\\10(e^x)^2-23(e^x)-5=0\\\\\text{substitution:}\ e^x=t > 0\\\\10t^2-23t-5=0\\\\10t^2-25t+2t-5=0\\\\5t(2t-5)+1(2t-5)=0\\\\(2t-5)(5t+1)=0\iff2t-5=0\ \vee\ 5t+1=0\\\\2t=5\ \vee\ 5t=-1\\\\t=\dfrac{5}{2} > 0\ \vee\ t=-\dfrac{1}{5} < 0\\\\\text{therefore}\ e^x=\dfrac{5}{2}\to\ln e^x=\ln\left(\dfrac{5}{2}\right)\\\\\boxed{x=\ln\left(\dfrac{5}{2}\right)}

5 0
2 years ago
Read 2 more answers
Mark earned $240 in the first week and earns $680 in the fifth week. How much will he earn in the 20th week (suppose his earning
Irina18 [472]

Answer:

$ 2330

Step-by-step explanation:

a = $240

Earning at the end of fifth week = $ 680

increase in earnings per weak = ( 680 -240)/2     = 440/2 =110

d =110

l = a + (n-1)d

a20 = 240 + (19 * 110 ) = 240 + 2090 =   2330

6 0
3 years ago
Read 2 more answers
In the number at the right circle the 4 that has 10 times the value of the underlined 4
Aleksandr [31]
I think you would multiply 4 and 10  and that equals 40.
7 0
3 years ago
Two boats leave a dock at the same time. One boat travels south at 32 mi divided by hr32 mi/hr and the other travels east at 60
TEA [102]

Answer: the rate at which the distance between the boats is​ increasing is 68 mph

Step-by-step explanation:

The direction of movement of both boats forms a right angle triangle. The distance travelled due south and due east by both boats represents the legs of the triangle. Their distance apart after t hours represents the hypotenuse of the right angle triangle.

Let x represent the length the shorter leg(south) of the right angle triangle.

Let y represent the length the longer leg(east) of the right angle triangle.

Let z represent the hypotenuse.

Applying Pythagoras theorem

Hypotenuse² = opposite side² + adjacent side²

Therefore

z² = x² + y²

To determine the rate at which the distances are changing, we would differentiate with respect to t. It becomes

2zdz/dt = 2xdx/dt + 2ydy/dt- - - -- - -1

One travels south at 32 mi/h and the other travels east at 60 mi/h. It means that

dx/dt = 32

dy/dt = 60

Distance = speed × time

Since t = 0.5 hour, then

x = 32 × 0.5 = 16 miles

y = 60 × 0.5 = 30 miles

z² = 16² + 30² = 256 + 900

z = √1156

z = 34 miles

Substituting these values into equation 1, it becomes

2 × 34 × dz/dt = (2 × 16 × 32) + 2 × 30 × 60

68dz/dt = 1024 + 3600

68dz/dt = 4624

dz/dt = 4624/68

dz/dt = 68 mph

6 0
3 years ago
Find the number of triangles with c =7, b=11, and B=21 degrees
muminat
<h3>Answer:</h3>

1

<h3>Step-by-step explanation:</h3>

The given angle is opposite the longest given side, so there will be exactly one solution.

_____

The number of solutions may be 0, 1, or 2 when the given angle is opposite the shortest given side.

6 0
2 years ago
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