Answer:
r(-1) = 6.31 and r(2) = -16.88
Step-by-step explanation:
* Lets read the problem and solve it
- Evaluate means find the value, so evaluate r(x) means find the value
of it at the given values of x
∵ r(x) = -0.21x³ + x² - 8.1x - 3
∵ x = -1 and x = 2
- Then find r(-1) by substitute x by -1 and find r(2) by substitute x by 2
# At x = -1
∴ r(-1) = -0.21(-1)³ + (-1)² - 8.1(-1) - 3
∴ r(-1) = -0.21(-1) + (1) - 8.1(-1) - 3
∴ r(-1) = 0.21 + 1 + 8.1 - 3
∴ r(-1) = 6.31
# At x = 2
∴ r(2) = -0.21(2)³ + (2)² - 8.1(2) - 3
∴ r(2) = -0.21(8) + (4) - 8.1(2) - 3
∴ r(2) = -1.68 + 4 - 16.2 - 3
∴ r(2) = -16.88
* r(-1) = 6.31 and r(2) = -16.88
Answer (apply the FOIL method)
X^2+8x+15
1 + 3 = 4;
9 x 4 = 36;
60 - 36 = 24;
2 x 24 = 48;
14 + 48 = 62;
-6 + 62 = 56.
Answer:
Ok, we know that we can write a horizontal translation as:
y' = f(x - A)
where if A is positive, this moves the graph of f(x) A units to the right.
Why is this?
Ok, let's compare:
y = f(x)
and
y' = f(x - A)
in y, when x = 0 we have f(0).
While to have this same point in y', we need to evaluate in x = A.
f(A - A) = f(0).
Then the value f(0) is now at x = A, this means that the point moved A units to the right.
And you can do this for all the values, so you will find that the entire graph of f(x) has ben moved A units to the right.
Answer:
(a) P(t) = 12100*(1.04^t)
(b) in 2008, estimate of population is 16560 (to the nearest integer)
Step-by-step explanation:
Population in 2000, P(0) = 12100
Growth rate = 4% each year
(a) function model for the t year after 2000 (exponential model)
P(t) = 12100*(1.04^t)
(b) for 2008,
P(2008-2000)
= P(8)
= 12100*(1.04^8)
= 12100 * 1.368569
= 16559.7
= 16560 (nearest integer)
