P(t)=6t
A(p)=πp^2, since p(t)=6t
A(t)=π(p(t))^2
A(t)=π(6t)^2
A(t)=36πt^2, so when t=8 and approximating π≈3.14
A(8)≈36(3.14)(8^2)
A(8)≈36(3.14)64
A(8)≈7234.56 u^2
Answer:
x=6
Step-by-step explanation:
9x+3y=36
3y=-9x+36
y=-3x+36
For lines to be perpendicular their slopes must be negative reciprocals of each other...mathematically:
m1*m2=-1 and in this case for a line to be perpendicular to y=-3x+36 that line must have a slope of:
-3m=-1, m=1/3 so
y=x/3+b, and using point (6,2) we can solve for b, the y-intercept...
2=6/3+b
2=3+b
b=-1 so the perpendicular line passing through the point (6,2) is:
y=x/3-1 or more neatly...
y=(x-3)/3
Answer:
<h3>Part A</h3>
The graph is non-linear as it is not a continuous straight line (with only one slope).
<h3>Part B</h3>
<u>Increasing</u>: the y-value increases as the x-value increases
<u>Constant</u>: the y-value stays the same as the x-value changes
<u>Decreasing</u>: the y-value decreases as the x-value increases
Therefore,
- Increasing segment: Between 0 and 2 seconds
- Constant segment: Between 2 and 3 seconds
- Decreasing segment: Between 3 and 5 seconds
<h3>Part C</h3>
For the first 2 seconds, the ant moves 6 cm from a hole in the tree at a steady speed of 3 cm per second. For the next second, the ant is at rest then turns around. For the next 2 seconds, the ant moves 6 cm back to the hole at a steady speed of 3 cm per second. The ant then stops.
<em><u>Krishna</u></em><em><u> Chauhan</u></em><em><u> roll</u></em><em><u> no</u></em><em><u> 24</u></em><em><u> class</u></em><em><u> </u></em><em><u>6</u></em><em><u>a</u></em><em><u> </u></em>