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My name is Ann [436]
3 years ago
14

Solve for x in the equation x2+20x+100=36

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
4 0
The answer is:
x = - 64 \div 22 = -2.909091
But if x2 was supposed to be x^2 then the answer is:
x =  - 4.-16
zalisa [80]3 years ago
4 0

Answer:

x = -4 and x = -16.

Step-by-step explanation:

We have the equation,

x^{2}+20x+100=36

i.e. x^{2}+20x+64=0

As the solution of a quadratic equation ax^{2}+bx+c=0 is given by x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}.

On comparing, a = 1, b = 20, c = 64.

So, the solution is,

x=\frac{-20\pm \sqrt{(20)^{2}-4\times 1\times 64}}{2a\times 1}.

i.e. x=\frac{-20\pm \sqrt{400-256}}{2}.

i.e. x=\frac{-20\pm \sqrt{144}}{2}.

i.e. x=\frac{-20\pm 12}{2}.

i.e. x=\frac{-20+12}{2} and x=\frac{-20-12}{2}.

i.e. x=\frac{-8}{2} and x=\frac{-32}{2}.

i.e. x = -4 and x = -16

Thus, the solution of the given equation is x = -4 and x = -16.

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