Answer:
5(2x-8)+15=-15
10x-40+15=-15
10x-25=-15
+25 +25 (add 25 to both sides)
____________
10x=10
divide by 10 on both sides
x=1
Well 2.5 + 2.5 is 5 so 5 - 2.5 is 2.5
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
So this problem would be written as this(:
so you start with 331 students together, but then you lose 7 who travel in the cars.
331-7=324
then it would be 324 divided by the 6 buses. that would look like this
324/6
that equals 54.
so in conclusion the answer is 54 students went into each bus:) hope that helps you!