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Sladkaya [172]
3 years ago
12

Simplify the following equation: 32^3/5

Mathematics
1 answer:
anyanavicka [17]3 years ago
3 0
32^3/5 = (2^5)^3/5 = 2^(5*3/5) = 2^3 = 8 
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Convert 48°36'12" to the nearest thousandth of a degree
uranmaximum [27]

48 degrees remains

divide minutes by 60

36/60 = 0.6

then divide seconds by 3600

12/3600=0.003 ( to nearest thousandth)

now add them all up

48 +0.6 + 0.003 = 48.603 degrees

5 0
4 years ago
Alberto is snowboarding down a mountain with a constant slope. the slope he is on has an overall length of 1560 feet. the top of
Olenka [21]

The slope of the equation is calculated as:

 \frac{h_2-h_1}{t_2-t_1}=m

Where h_2 is the height of the upper part of the slope and h_1 is the height of the low er part.

 m=\frac{4000-4600}{24-0}

m=-25

So, the equation of the line is:

h-4600=-25(t-0)

h=-25t+4600

With this equation we can find the height of Alberto after having passed 10 sec.

h(10)=-25 (10)+4600\\h(10)=-250+4600\\h(10)=4350

 After 10 seconds Alberto is 350 feet from the bottom of the slope.

Alberto's speed is:

v=\frac{1560ft}{24s}=65ft/s

The speed in miles per hour is:

v=65ft /s*\frac{1 mile}{5280 ft}*\frac{3600s}{1 hour}\\v=44.32 miles/h

4 0
4 years ago
Juan has 18 posters. Ten of those posters show athletes. what is a ratio of the number of posters that show athletes to the tota
nirvana33 [79]
I believe it's 10:18
3 0
3 years ago
Read 2 more answers
How do you simplify (4+2i)(3-i)
ludmilkaskok [199]
You simplify it by doing distributive property like this

(4+2i)(3-i) =12-4i+6i-2i2

now add common like numbers 

12+2i-2i2

Now on the i that is squared change the i to a -1 and get this

12+2i+2

Now again add common like numbers and get

14+2i that would be your answer
hope this helped
5 0
3 years ago
6x - 5 + x <br><br><br> No one:<br> Someone when I answer the question right:
MAVERICK [17]

Answer: 7x - 5

Step-by-step explanation:

The expression given in the question is:

= 6x - 5 + x

We have to collect like terms. This will be:

= 6x + x - 5

= 7x - 5

4 0
3 years ago
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