5, because the spouse can be an exemption if not claimed as a dependent on another person's return. The head of household is an exemption as the person doing the return and all kids.
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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<span>x + 6y = 2
4x - 3y = 10
The first thing to do when solving a system of equations using the addition/elimination method is to multiply one or both of the equation by a value that will cancel out one of the variable terms.
Based on this, the correct answer is D - multiply the bottom equation by 2 thus eliminating the y variable when the equations are added together:
</span>x + 6y = 2 x + 6y = 2
2(4x - 3y = 10) --> 8x - 6y = 20<span>
Hope this helps.</span>
Answer:
Step-by-step explanation:
Volume=(pi)(radius^2)(height)
Volume=(pi)(5^2)(12)
V=(pi)(25)(12)
V=(pi)(300)
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What is a kobo stemp
Step-by-step explanation: