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sammy [17]
3 years ago
13

Rewrite the expression in the picture in the form y^n.

Mathematics
2 answers:
sergeinik [125]3 years ago
7 0

Answer:

y^(2/3)

Step-by-step explanation:

( y ^ ( 7/3) * y^ ( 1/3)  ) ^ 1/4

Combine the terms in side the parentheses

a^b* a^c = a^(b+c)

( y ^ ( 7/3+ 1/3)  ) ^ 1/4

( y^( 8/3) )^1/4

We know a^b^c = a^(b*c)

y ^(8/3*1/4)

y^(2/3)

iren2701 [21]3 years ago
5 0

Step-by-step explanation:

here's the answer to your question

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Pls help I’ll brainlest ASAP and add extra points I’m failing
Step2247 [10]

Step-by-step explanation:

you drew already the right things, you have everything.

so, what is the problem ?

the most common form of line equation is

y = ax + b

a is the slope of the line. it is expressed as the ratio

y coordinate change / x coordinate change

when going from one point to the other.

b is the y-intercept (the y value when x = 0).

once we have the slope, we get b by using the coordinates of one of the given points as x and y in the equation and solve for b.

so, for the 2 marked points you showed correctly the differences :

x changes by +8 (from -4 to 4).

y changes by -2 (from 3 to 1).

so the slope is -2/+8 = -1/4

the y-intercept we also see directly in the chart : +2.

3 0
3 years ago
Slope of 2 and passes through the point (-4,3). Write the equation in slope intercept form
erastova [34]

Answer:

The equation is y = 2x + 11.

Step-by-step explanation:

It is given that the gradient of the equation is 2. Using slope-form formula, y = mx+b where m is gradient and b is y-intercept. In order to find b, you have to substitute x-coordinate and y-coordinate into the equation :

y = mx + b

m = 2

At(-4,3),

3 = 2(-4) + b

b = 3 - 2(-4)

= 11

8 0
3 years ago
Assume that y varies directly with x. If y = 17 when x = –17, find y when x = –4.
serg [7]

answer =

y = kx ⇒

k = y/x = 5/7

6 0
3 years ago
What does this equal
nikklg [1K]
X-2x is the answer good luck
4 0
4 years ago
Find any relative extrema of the function. (Round your answers to three decimal places.)
Strike441 [17]

(x) = arcsec(x) − 8x

f'(x) = d/dx( arcsec(x) − 8x )

<span> 1/xsqrt( x^2 - 1) - 8</span>

f'(x) = 0

1/xsqrt( x^2 - 1) - 8 = 0

8 x sqrt (x^2-1) = 1

<span> ( 8 x sqrt (x^2-1) )^2 = 1</span>

64 x^2 ( x^2 - 1) = 1

64 x^4 - 64 x^2 =1

64 x^4 - 64 x^2 - 1 = 0

x = 1.00766 , - 1.00766

<span> x =   - 1.00766</span>

f(- 1.00766) = arcsec(- 1.00766) − 8( - 1.00766)

f( - 1.00766 ) = 11.07949

x = 1.00766

f(1.00766) = arcsec(1.00766) − 8( 1.00766)

f(1.00766 ) = -7.93790

relative maximum (x, y) = (- 1.00766 , 11.07949 ) relative minimum (x, y) = ( 1.00766 , -7.93790  )


8 0
4 years ago
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