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sammy [17]
2 years ago
13

Rewrite the expression in the picture in the form y^n.

Mathematics
2 answers:
sergeinik [125]2 years ago
7 0

Answer:

y^(2/3)

Step-by-step explanation:

( y ^ ( 7/3) * y^ ( 1/3)  ) ^ 1/4

Combine the terms in side the parentheses

a^b* a^c = a^(b+c)

( y ^ ( 7/3+ 1/3)  ) ^ 1/4

( y^( 8/3) )^1/4

We know a^b^c = a^(b*c)

y ^(8/3*1/4)

y^(2/3)

iren2701 [21]2 years ago
5 0

Step-by-step explanation:

here's the answer to your question

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How many bits are required to represent the decimal numbers in the range from 0 to 999 in straight binary code?
ad-work [718]
Note that powers of 2 can be written in binary as

2^0=1_2
2^1=10_2
2^2=100_2

and so on. Observe that n+1 digits are required to represent the n-th power of 2 in binary.

Also observe that

\log_2(2^n)=n\log_22=n

so we need only add 1 to the logarithm to find the number of binary digits needed to represent powers of 2. For any other number (non-power-of-2), we would need to round down the logarithm to the nearest integer, since for example,

2_{10}=10_2\iff\log_2(2^1)=\log_22=1
3_{10}=11_2\iff\log_23=1+(\text{some number between 0 and 1})
4_{10}=100_2\iff\log_24=2

That is, both 2 and 3 require only two binary digits, so we don't care about the decimal part of \log_23. We only need the integer part, \lfloor\log_23\rfloor, then we add 1.

Now, 2^9=512, and 999 falls between these consecutive powers of 2. That means

\log_2999=9+\text{(some number between 0 and 1})

which means 999 requires \lfloor\log_2999\rfloor+1=9+1=10 binary digits.

Your question seems to ask how many binary digits in total you need to represent all of the numbers 0-999. That would depend on how you encode numbers that requires less than 10 digits, like 1. Do you simply write 1_2? Or do you pad this number with 0s to get 10 digits, i.e. 0000000001_2? In the latter case, the answer is obvious; 1000\times10=10^4 total binary digits are needed.

In the latter case, there's a bit more work involved, but really it's just a matter of finding how many number lie between successive powers of 2. For instance, 0 and 1 both require one digit, 2 and 3 require two, while 4-7 require three, while 8-15 require four, and so on.
8 0
3 years ago
Find the values of x and y using the give chord, secant, and tangent lengths
garri49 [273]

Answer: 7

Step-by-step explanation:

7

3 0
3 years ago
Lcm of 2/5 and 5/18?
SSSSS [86.1K]

Answer:

10

Step-by-step explanation:

4 0
3 years ago
What is 2 3/8 in a improper fraction?
FromTheMoon [43]

Answer:

See below a shorter way to convert 2 3 8 to an improper fraction. Step 1: Multiply the whole number part (2) by the denominator (8). Step 2: Add the product from Step 1 (16) to the numerator (3). Step 3: Write that result (19) above the denominator.

Step-by-step explanation:

hope this helps you if it does plz mark brainiest

4 0
2 years ago
Read 2 more answers
Next term in the sequence 6 9 15 24
Klio2033 [76]
36

It is going up by odd numbers.

So the next term would be 24+12=36
7 0
2 years ago
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