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ivanzaharov [21]
3 years ago
15

Edgar accumulated $5,000 in credit card debt. If the interest is 20% per year and he does not make any payment for 2 years. How

much will he owe on this debt in 2 years by compounding continously?​
Mathematics
2 answers:
Nostrana [21]3 years ago
6 0

Answer:

$7,459.12

Step-by-step explanation:

The formula for continuous compounding is

A = Pe^(rt), where P is the original amount, A is the accumulated amount, r is the interest rate as a decimal fraction, and t is the number of years.  We want to know how much he will owe on this original $5,000 credit card debt after 2 years.

A = $5,000e^(0.20*2)

   = $7,459.12

Naddika [18.5K]3 years ago
4 0

Answer:

It’s 7,434.57

Step-by-step explanation:

It’s on my homework :/

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I don't understand how to solve this pls help
Charra [1.4K]

the sine function is a many-to-one function and therefore has no inverse function.

However if the domain is restricted to -90° ≤ x ≤ 90°

Then the function is one-to-one for this domain

Thus, sin^{-1} x is defined as the angle such that - π/2 ≤ x ≤ π/2

5π/6 is therefore outwith the domain



7 0
4 years ago
Does bin width matter when it comes to histograms? Why or why not?
maw [93]

Answer:

Avoid histograms with small bin widths that group data into lots of bins. A histogram constructed with small bin widths will show the distribution as a “pancake.” so no it does not help us see the pattern in the data.

Step-by-step explanation:

4 0
3 years ago
When a force of 30 N acts on a certain object the acceleration of the object is 5m/s2 if the force is changed to 54 N what will
PtichkaEL [24]

Answer:

The correct answer is 9 m per second^{2}

Step-by-step explanation:

Force is defined by mass of an object times it's acceleration.

Let the mass of the object be m kilograms.

When a force of 30 N acts on a certain object the acceleration of the object is 5 m per second^{2}

∴ 30 = m × 5

⇒ m = 6.

If the force is changed to 54 N, let the acceleration of the object be x  m per second^{2}.

∴ 54 = m × x

⇒ x = \frac{54}{6} = 9

Thus when the force is 54 N, the acceleration of the object is 9 m per second^{2}.

6 0
4 years ago
Which is the solution set to the inequality (4x-3)(2x-1)&gt=0?
Serjik [45]

(4x - 3)(2x - 1) ≥ 0

First, find the zeros:

4x - 3 = 0         2x - 1 = 0

x = \frac{3}{4}               x = \frac{1}{2}

Next, plot these points and choose test points on the outside and between the zeros:

←-------0------\frac{1}{2}------\frac{5}{8}------\frac{3}{4}------1------→

Lastly, plug in the test points and look for a positive result (since it is greater than 0).

Test Point 0: [4(0) - 3][2(0) - 1]  = ( - )( - ) = +  THIS WORKS!

Test Point \frac{5}{8}: [4(\frac{5}{8}) - 3][2(\frac{5}{8}) - 1]  = ( - )( + ) = -  <em>This does NOT work</em>

Test Point 1: [4(1) - 3][2(1) - 1]  = ( + )( + ) = +  THIS WORKS!

Answer: x ≤ \frac{1}{2}   or   x ≥ \frac{3}{4}

Interval Notation: (-∞, \frac{1}{2}] U [\frac{3}{4}, ∞)

Graph: ←------\frac{1}{2}          \frac{3}{4}--------→

5 0
3 years ago
Multiply the expression (3y-8)(-c+y)
GarryVolchara [31]

Answer:

-3yc+3y2+8c-8y

Step-by-step explanation:

(3y-8)(-c+y)

3y(-c+y)-8(-c+y)

-3yc+3y2+8c-8y

8 0
4 years ago
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