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3 years ago

Which picture illustrates the prophase stage of mitosis?

Mathematics

2 answers:

posledela3 years ago

7 0

The answer is B. where nuclear membranes form around each set of chromosomes resulting in two nuclei.

netineya [11]3 years ago

3 0

Prophase is when the nuclear envelope is starting to break down and the chromatin is condensing. The picture that illustrates this is D.

For reference...
Picture A - Anaphase
Picture B - Telophase
Picture C - Metaphase
Picture D - Prophase

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Someone plssss help ILL GIVE BRAINLIEST

Naily [24]

Answer:

x = 22 degrees

Step-by-step explanation:

Since this is a right angle and both angles added together will equal to 90degrees this means that:

(3x-5) + (x+7) = 90

(first, remove the brackets)

3x-5+x+7 = 90

( add the numbers together and the term x together)

( 3x+x ) + ( -5+7 ) = 90

4x + 2 = 90

(subtract 2 from both sides)

4x = 88

(divide by 4 from both sides)

x = 22

so the measure of x = 22 degrees

4 0

3 years ago

Choose one of the factors of x15 − 64. (2 points)

Lorico [155]

We have been given the function $x^{15}-64$

Convert this expression in difference of cubes form.

$x^{15}-64\\=(x^5)^3-4^3$

Now, in order to find the factors, we can apply the difference of cubes form, which is given by

$x^3-y^3=(x-y)(x^2+xy-y^2)$

On applying this formula, we get

$(x^5-4)(x^{10}+4x^5+16)$

Hence, the factors of the given expression are

$(x^5-4) \text{ and }(x^{10}+4x^5+16)$

Out of the given option, A is the correct option.

x^5 − 4 is the required factor.

6 0

3 years ago

Read 2 more answers

Solve 54=y−14 please help meeeeee

Inessa05 [86]

Answer:

y=68

Step-by-step explanation:

54=y−14

54+14=y

68=y

5 0

3 years ago

20 - 4 TIMES 4 DIVIDE 2 + 3

Tanya [424]

$20 - 4 \times 4 \div 2 + 3$

Using BODMAS formula, we see that we have first divide, then multiply, then add and finally subtract
So
$20 - 4 \times 4 \div 2 + 3 \\ = 20 - 4 \times 2 + 3 \\ = 20 - 8 + 3 \\ = 23 - 8 \\ = 15$

<h3>Answer:</h3>

<h3>Hope it helps..</h3>

ray4918 here to help

8 0

3 years ago

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The figure shows a rectangle ABCD where the diagonals AC and BD intersect E. Given that BEC=52.

denis23 [38]

Ii is the correct answer and try using photomath it helps ;)

3 0

2 years ago