3 years ago

I NEED HELP !!!! PLEASEEEEEEEEEEEE

Mathematics

1 answer:

tankabanditka [31]3 years ago

4 0

Vertex form: y = (x + 1)^2 - 25
vertex: (-1, -25)

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2x²-5x-12=0 (simplify solution set)

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Step-by-step explanation:

To simplify and solve this, let's use the quadratic formula.

So the format of a quadratic equation is supposed look like this:

$ax^2+bx+c=0$

Let's find a, b, c:

a is the coefficient of x^2
b is the coefficient of x
c is the constant term

Now let's solve the equation.

Let's solve your equation step-by-step.

2x^2−5x−12=0

For this equation: a=2, b=-5, c=-12

2x^2+−5x+−12=0

Step 1: Use quadratic formula with a=2, b=-5, c=-12.

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-12)} }{2(2)}$

$x=\frac{5\pm\sqrt{121} }{4}$

$x=4$ or $x=\frac{-3}{2}$

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<u>Answer:</u>

x = 4 or x = -3/2

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