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Lorico [155]
3 years ago
9

Ranjit titrates a sample 10.00 mL of Ba(OH)2 solution to the endpoint using 12.58 mL of 0.1023 M H2SO4.

Chemistry
1 answer:
julia-pushkina [17]3 years ago
5 0

<u>Answer:</u> The concentration of Ba(OH)_2 comes out to be 0.129 M.

<u>Explanation:</u>

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ba(OH)_2

We are given:

n_1=2\\M_1=0.1023M\\V_1=12.58mL\\n_2=2\\M_2=?M\\V_2=10.00mL

Putting values in above equation, we get:

2\times 0.1023\times 12.58=2\times M_2\times 10.00\\\\M_2=0.129M

Hence, the concentration of Ba(OH)_2 comes out to be 0.129 M.

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3 years ago
Pulses A, B, C, and D all travel at 10 m/s on the same string but in opposite directions. The string is depicted at time t=0 in
Anit [1.1K]

(a) The displacement of point P at time t=0.10s is determined as +2cm.

(b) The displacement of point P at time t=0.20s is determined as -2cm.

<h3>What is displacement?</h3>

Displacement is the change in position of an object. It is obtained from the product of velocity and time of motion.

x = vt

<h3>Displacement of the waves after 0.1 s</h3>

x = 10 m/s x 0.1 s = 1 m

Each wave will travel 1 m to the right or to the left, depending on the initial direction.

  • wave B from left will stop at point 0 m
  • wave A from left will stop at point -1 m
  • wave C from right will stop at point 0 m
  • wave D from right will stop at point + 1 m

wave B and C superimposed and the displacement will be between A and D.

Amplitude of A = - 2cm

Amplitude of D = + 4cm

Displacement of point P = 4 cm - 2 cm =  2cm

<h3>Displacement of the waves after 0.2 s</h3>

x = 10 m/s x 0.1 s = 2 m

Each wave will travel 2 m to the right or to the left, depending on the initial direction.

  • wave B from left will stop at point 1 m
  • wave A from left will stop at point 0 m
  • wave C from right will stop at point -1 m
  • wave D from right will stop at point 0 m

Displacement of point P = (amplitude B + amplitude C) + (amplitude A + amplitude D)

Displacement of point P= (2cm - 2cm) + (2 cm - 4cm)= -2cm

Learn more about displacement here: brainly.com/question/2109763

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Answer:

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Explanation:

1. Peak ≥ 160 ppm

The formula C₄H₈O shows that the Index of Hydrogen Deficiency = 1.

It could be caused by either a ring or a double bond.

A peak at ≥ 160 ppm strongly indicates a C=O group, so the rest of the molecule can contain no rings or double bonds.

There are no other heteroatoms, so the compound most be an aldehyde or a ketone.

One compound that meets these criteria is butyraldehyde, CH₃CH₂CH₂CH=O (see Fig. 1.)

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If all peaks are < 160 ppm, there can no C=O group.

There is no ring, so there must be a C=C double bond.

There is no other unsaturation, so the O atom must be present as an alcohol or an ether.

One compound that meets these criteria is but-3-en-1-ol, CH₂=CHCH₂CH₂OH (see Fig. 2).

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