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Daniel [21]
4 years ago
8

To use the gas law constant R = 0.0821, the unit for temperature should be Kelvin and the unit for volume should be milliliters.

Chemistry
2 answers:
valkas [14]4 years ago
8 0

The answer is definetely False

valkas [14]4 years ago
3 0

Answer: The statement that unit for temperature should be Kelvin and the unit for volume should be milliliters is False.

Explanation:

According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = 1 atm  (at STP)

V= Volume of the gas = 22.4 L   (at STP)

T= Temperature of the gas =  273 K   (at STP)    

R= Gas constant = ?

n=  moles of gas= 1 mol

R=\frac{PV}{nT}=\frac{1\times 22.4}{1\times 273}=0.0821Lam/Kmol

Thus the unit for temperature should be Kelvin and the unit for volume should be Liters.

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List and discuss at least 4 reasons why a laboratory should operate using GLP.
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Answer:

The list and discussions are stated below:

Explanation:

Good Laboratory Practice (GLP) is extremely important.

1. Organization

With GLP we can guarantee an organized work environment, which is essencial in a laboratory.

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GLP promotes laboratory safety for personell, avoiding unecessary risks and preventing accidents.

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7 0
4 years ago
What is the molar mass of chlorine gas? (Hint: Be careful... the gas exists as Cl2)
Sergio039 [100]
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5 0
3 years ago
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GenaCL600 [577]
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3 0
3 years ago
Calculate the number of atoms in 1.0 mole of O2​
natali 33 [55]

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7 0
3 years ago
Write the full electron configuration of calcium.
tangare [24]

Answer: 1s^22s^22p^63s^23p^64s^2 , oxidation state = +2

Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom. The electrons are filled according to Afbau's rule in order of increasing energies.

The electronic configuartion of Calcium with atomic number 20  is :

Ca:20:1s^22s^22p^63s^23p^64s^2

As calcium can easily lose its two valence electrons to attain stability , its oxidation state is +2.

Ca^{2+}:18:1s^22s^22p^63s^23p^6

7 0
3 years ago
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