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Daniel [21]
3 years ago
8

To use the gas law constant R = 0.0821, the unit for temperature should be Kelvin and the unit for volume should be milliliters.

Chemistry
2 answers:
valkas [14]3 years ago
8 0

The answer is definetely False

valkas [14]3 years ago
3 0

Answer: The statement that unit for temperature should be Kelvin and the unit for volume should be milliliters is False.

Explanation:

According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = 1 atm  (at STP)

V= Volume of the gas = 22.4 L   (at STP)

T= Temperature of the gas =  273 K   (at STP)    

R= Gas constant = ?

n=  moles of gas= 1 mol

R=\frac{PV}{nT}=\frac{1\times 22.4}{1\times 273}=0.0821Lam/Kmol

Thus the unit for temperature should be Kelvin and the unit for volume should be Liters.

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What is the mass, in grams, of 1.4 mol W
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Atomic mass W = 183.84 u.m.a

1 mole --------- 183.84
1.4 moles ---- ?

1.4 x 183.84 / 1 = 257.376 g

hope this helps!
3 0
3 years ago
The question is in the attached word document.
Alekssandra [29.7K]

Answer:i read it Explanation:

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Two systems with heat capacities 19.9 J mol-1 K-1 and 28.2 ] mol 1 K-1 respectively interact thermally and come to an equilibriu
MAVERICK [17]

Answer : The initial temperature of system 2 is, 19.415^oC

Explanation :

In this problem we assumed that the total energy of the combined systems remains constant.

-q_1=q_2

m\times c_1\times (T_f-T_1)=-m\times c_2\times (T_f-T_2)

The mass remains same.

where,

C_1 = heat capacity of system 1 = 19.9 J/mole.K

C_2 = heat capacity of system 2 = 28.2 J/mole.K

T_f = final temperature of system = 30^oC=273+30=303K

T_1 = initial temperature of system 1 = 45^oC=273+45=318K

T_2 = initial temperature of system 2 = ?

Now put all the given values in the above formula, we get

-19.9J/mole.K\times (303-318)K=28.2J/mole.K\times (303-T_2)K

T_2=292.415K

T_2=292.415-273=19.415^oC

Therefore, the initial temperature of system 2 is, 19.415^oC

8 0
4 years ago
Examine the statement.
vlada-n [284]

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Explanation:

5 0
3 years ago
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3 years ago
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