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3 years ago

To use the gas law constant R = 0.0821, the unit for temperature should be Kelvin and the unit for volume should be milliliters.

Chemistry

2 answers:

valkas [14]3 years ago

8 0

The answer is definetely False

valkas [14]3 years ago

3 0

Answer: The statement that unit for temperature should be Kelvin and the unit for volume should be milliliters is False.

Explanation:

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = 1 atm (at STP)

V= Volume of the gas = 22.4 L (at STP)

T= Temperature of the gas = 273 K (at STP)

R= Gas constant = ?

n= moles of gas= 1 mol

$R=\frac{PV}{nT}=\frac{1\times 22.4}{1\times 273}=0.0821Lam/Kmol$

Thus the unit for temperature should be Kelvin and the unit for volume should be Liters.

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The process n01 → p11 + β−10 n 0 1 → p 1 1 + β - 1 0 represents a(n) _____.

polet [3.4K]

Answer:

beta decay

Explanation:

The process is represented by the nuclear equation:

$^1_0n$ → $^1_1p+^0_{-1}\beta$

Where:

n represents a neutron,
p represents a proton, and
β represents an electron.

The superscripts to the leff of each symbol is the mass number (number of protons and neutrons), and the subscript to the left means the atomic number (number of protons).

Then, in this process a neutron is being transformed into a proton by the emssion of an electron (from inside the nucleus of the atom).

This electron is named beta (β) particle, and the process is called beta decay, because the neutron is changing into other subatomic particles.

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3 years ago

Jada Peterson

barxatty [35]

Answer: A

Explanation:

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3 years ago

Which coefficient before potassium (K) balances this chemical equation?

miskamm [114]

Answer:

The coefficient before potassium (K) balances this chemical equation is 2.

Explanation:

_K +Cl₂ → 2KCl

K =1 ; Cl =2

K=1 × 2 = 2

Cl = 1 × 2 = 2

2 K +Cl₂ = 2 KCl

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3 years ago

Read 2 more answers

Hydrogen gas (a potential future fuel) can be formed by the reaction of methane with water according to the following equation:

rusak2 [61]

Answer:

60.42% is the percent yield of the reaction.

Explanation:

Moles of methane gas at 734 Torr and a temperature of 25 °C.

Volume of methane gas = V = 26.0 L

Pressure of the methane gas = P = 734 Torr = 0.9542 atm

Temperature of the methane gas = T = 25 °C = 298.15 K

Moles of methane gas = n

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.9542 atm\times 26.0L}{0.0821 atm L/mol K\times 298.15 K}=1.0135 mol$

Moles of water vapors at 700 Torr and a temperature of 125 °C.

Volume of water vapor = V' = 23.0 L

Pressure of water vapor = P' = 700 Torr = 0.9100 atm

Temperature of water vapor = T' = 125 °C = 398.15 K

Moles of water vapor gas = n'

$P'V'=n'RT'$

$n'=\frac{PV}{RT}=\frac{0.9100 atm\times 23.0L}{0.0821 atm L/mol K\times 398.15 K}=0.6402 mol$

$CH_4(g)+H_2O(g)\rightarrow CO(g)+3H_2(g)$

According to reaction , 1 mol of methane reacts with 1 mol of water vapor. As we can see that moles of water vapors are in lessor amount which means it is a limiting reagent and formation of hydrogen gas will depend upon moles of water vapors.

According to reaction 1 mol of water vapor gives 3 moles of hydrogen gas.

Then 0.6402 moles of water vapor will give:

$\frac{3}{1}\times 0.6402 mol=1.9208 mol$ of hydrogen gas