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fenix001 [56]
3 years ago
6

If Jimin is 5'9" and Namjoon is 5'11" what is the difference in height? (You don't have to answer this)

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
8 0
3" is the difference in height.
sertanlavr [38]3 years ago
6 0
3" is the difference in the height
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Which is the slope of the line that passes through the points (3,5) and (8,7)?
Hatshy [7]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

m=\boxed{\frac{2}{5}}

»»————- ★ ————-««  

Here’s why:  

  • The formula for the slope of two given lines given is 'rise over run'.

⸻⸻⸻⸻

\boxed{\text{Slope Formula:}}\\\\\frac{y_2-y_1}{x_2-x_1}\\\\\rightarrow (x_1,y_1),(x_2,x_1) - \text{Two Points Given}

⸻⸻⸻⸻

  • We are given the points (3,5) and (8,7).

⸻⸻⸻⸻

\boxed{\text{Finding the Slope:}}\\\\\rightarrow m=\frac{7-5}{8-3}\\\\\rightarrow \boxed{m=\frac{2}{5}}

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

7 0
3 years ago
PLEASE HELP! Here's my word problem; A rectangular riding arena is 45 meters long. The stables are 10 meters wide and 26.6 meter
Pavlova-9 [17]

Answer:

38

Step-by-step explanation:

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7 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
RoseWind [281]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
One equation in a system of equations with no solution is y=-20 +5.
Trava [24]

Answer:

the answerr is i9 dont know haha bum

Step-by-step explanation:

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6 0
2 years ago
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Please helpy mey :P<br><br> Graph f(x)=−3/4x−4 .
kap26 [50]
You need 2 points in order to draw this first put x=0 and you will find y= - 4 then solve
0 =  - (3 \div 4)x - 4

6 0
3 years ago
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