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3 years ago

If Jimin is 5'9" and Namjoon is 5'11" what is the difference in height? (You don't have to answer this)

Mathematics

2 answers:

xz_007 [3.2K]3 years ago

8 0

3" is the difference in height.

sertanlavr [38]3 years ago

6 0

3" is the difference in the height

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Please hurry it’s missing

Blizzard [7]

Answer:

77/15 = 5.133

Step-by-step explanation:

3 and 2/3 = 11/3

1 and 2/5 = 7/5

$\frac{11}{3} * \frac{7}{5} = \frac{77}{15}$

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3 years ago

Find the area of a rhombus if its diagonals are of lengths 12.8 cm and 8.4cm

Daniel [21]

Area =

$\frac{pq}{2}$

where p and q are it's diagonal

so according to the rule.

$\frac{12.8 \times 8.4}{2}$

$\frac{107.52}{2}$

$53.76 \\ \\$

is the answer.

hope understands 

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1 year ago

Use the quadratic formula to find the solutions for.. y = 2x^2 - 9x + 5.

Yakvenalex [24]

Answer: $x=\frac{9}{4}-\frac{\sqrt{41} }{4} \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}$

Step-by-step explanation:

$2x^2-9x+5$

a=2

b=-9

c=5

$x=\frac{-b\frac{+}{}\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-9)\frac{+}{}\sqrt{(-9)^2-4(2)(5)} }{2(2)}$

$x=\frac{9\frac{+}{}\sqrt{81-40} }{4}$

$x=\frac{9\frac{+}{}\sqrt{41} }{4}$

$x=\frac{9}{4}-\frac{\sqrt{41} }{4} \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}$

4 0

3 years ago

julia-pushkina [17]

$V = \frac{1}{3} \pi r^2h \ \ \ \ \text{[r=radius, h=height ]} \\ \\ V = \frac{1}{3}*(5)^2*11 * \pi = \frac{1}{3}*25*11 * \pi = \frac{275}{3} \pi =91 \frac{2}{3} \pi \ units^3$

B.

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4 years ago

What is a constraint in algebra?

givi [52]

Answer:

The constant in an algebraic expression is the number part of the expression for example.. IN 2x 2 is the constant it doesn't change and x is variable it may vary

3 0

3 years ago

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