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3 years ago

If an inequality uses the phrase at most, it will require a greater than symbol

Mathematics

2 answers:

RoseWind [281]3 years ago

6 0

The answer is false, your welcome

Katyanochek1 [597]3 years ago

5 0

Answer:

false

Step-by-step explanation:

at most would require an less than or equal to symbol

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An online ticket seller charges $44 for each ticket to a concert, plus a fixed handling fee of $12. Define the unknown variables

const2013 [10]

The unknown variables are how many tickets are being bought and the total.

t=tickets

x=total

44t+12=x

6 0

4 years ago

The pesticide diazinon is in common use to treat infestations of the German cockroach, Blattella germanica. A study investigated

cluponka [151]

Answer:

We conclude that there is no difference in the proportion of cockroaches that died on each surface.

Step-by-step explanation:

We are given that a study investigated the persistence of this pesticide on various types of surfaces.

After 14 days, they randomly assigned 72 cockroaches to two groups of 36, placed one group on each surface, and recorded the number that died within 48 hours. On the glass, 18 cockroaches died, while on plasterboard, 25 died.

Let $p_1$ = proportion of cockroaches that died on glass surface.

$p_2$ = proportion of cockroaches that died on plasterboard surface.

So, Null Hypothesis, $H_0$ : $p_1-p_2$ = 0 {means that there is no difference in the proportion of cockroaches that died on each surface}

Alternate Hypothesis, $H_A$ : $p_1-p_2\neq$ 0 {means that there is a significant difference in the proportion of cockroaches that died on each surface}

The test statistics that would be used here Two-sample z proportion statistics;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of cockroaches that died on glass surface = $\frac{18}{36}$ = 0.50

$\hat p_2$ = sample proportion of cockroaches that died on plasterboard surface = $\frac{25}{36}$ = 0.694

$n_1$ = sample of cockroaches on glass surface = 36

$n_2$ = sample of cockroaches on plasterboard surface = 36

So, test statistics = $\frac{(0.50-0.694)-(0)}{\sqrt{\frac{0.50(1-0.50)}{36}+\frac{0.694(1-0.694)}{36} } }$

= -1.712

The value of z test statistics is -1.712.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that there is no difference in the proportion of cockroaches that died on each surface.

8 0

3 years ago

What is the solution of the system of linear equations?

Monica [59]

-3x+4y=-18
2x-y=7
the answer qould be C.(2,-3)
-3(2)+4(-3)=-18
-6+(-12)=-18
-18=-18

2(2)-(-3)=7
4+3=7
7=7

C.

8 0

3 years ago

Read 2 more answers

Using mathematical induction prove whether or not the following statement is true for all positive integers n, or show why it is

aniked [119]

Base case: For $n=1$ , the left side is 2 and the right is $2\cdot1^2=2$ , so the base case holds.