Answer:
Step-by-step explanation:
- V(x) = x³ - 8x² + 19x - 12
<u>The two of the dimensions given</u>
<u>and the third one is</u>
<u>Multiply the three dimensions to get the volume:</u>
- (x - 1)(x - 3)(x + a) =
- (x² - 4x + 3)(x + a) =
- x³ - 4x² + 3x + ax² - 4ax + 3a =
- x³ - (4 - a)x² + (3 - 4a)x + 3a
Comparing with the given function, we get a = - 4
<u>So the missing dimension is:</u>
6a^3 : 3a = 2a^3-1 = 2a^2
The quotient is 2a^2
Hope it helped
The height of the parallelogram is 8 because using the pythagorean theorem, a^2+b^2=c^2
6^2+x^2=10^2
36+x^2=100
100-36=64
square root of 64=8
area of parallelogram:
a=bh
a=8*14
a=112 units ^2
hope this helps!
Answer:
Choice B
Step-by-step explanation:
Given radical expression:
![\sqrt[4]{1296 {x}^{16} {y}^{12} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B1296%20%7Bx%7D%5E%7B16%7D%20%20%7By%7D%5E%7B12%7D%20%7D%20)
To Find:
The Simpler form of this expression
Soln:
![= \sqrt[4]{1296 {x}^{16} {y}^{12} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%5B4%5D%7B1296%20%7Bx%7D%5E%7B16%7D%20%20%7By%7D%5E%7B12%7D%20%7D%20)
We could re-write the given expression, according to the law of exponents:
![= \tt \sqrt[4]{(6x {}^{4}y {}^{3}) {}^{4} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Ctt%20%5Csqrt%5B4%5D%7B%286x%20%7B%7D%5E%7B4%7Dy%20%7B%7D%5E%7B3%7D%29%20%20%7B%7D%5E%7B4%7D%20%20%7D%20)
Now we need to bring terms out of the radical as:
Bring out 6x^4 from the absolute & put y^3 only in it:
Choice B is accurate.
