I think it’s 4.308 when u multiply
The value of this account in 10 years is given by the formula:
FV = P*(1+r)^t
where FV is the future value in the account after 10 years(to be calculated)
P is the principal invested at the beginning
r is the interest rate and
t is the time horizon in years
Given, Invested Amount (P) = 20,000
Interest rate (r) = 5.5% = 0.055
Time horizon (t) = 10 years = 10
Substituting the formula, FV = 20,000*(1+0.055)^10 = 20,000*1.055^10 = 20,000*1.708144458 = 34,162.89
The value of this account after 10 years =$34,162.89 (Rounded to the nearest cent)
Answer:
f(g(2))=84
Step-by-step explanation:
Step one:
Given data
f(x)= x*2 +3
g(x) = 4x + 1
Step two
Let us find g(2) first then we proceed to find f(g(2))
g(2)=4(2) +1
g(2)=8+1
g(2)=9
Since g(2)=9
f(g(2))=x*2 +3
f(g(2))=9*2 +3
f(g(2))=81+3
f(g(2))=84
Answer:
Step-by-step explanation:
409515 Is the answer because you round up because the hundredths place number is greater than 5 so you round up, BUT you gotta roung 9 up but then you gotta add 1 to the ones place
Answer:
The coach can choose a lineup of 11 players in 6,047,981,701,347 different ways.
Step-by-step explanation:
Since the varsity soccer team has 20 players, and three of the players are trained to be goalies while the remaining 17 can play any position, and only 11 players can be on the field at once, and the coach wants to make sure there is exactly one goalie on the field, to determine how many ways can the coach choose a lineup of 11 players if exactly 1 player must be a goalie the following calculation has to be made:
3 x 17 ^ 10 = X
3 x 2,015,993,900,449 = X
6,047,981,701,347 = X
Therefore, the coach can choose a lineup of 11 players in 6,047,981,701,347 different ways.
