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victus00 [196]
3 years ago
10

Q22.

Mathematics
1 answer:
DENIUS [597]3 years ago
8 0

Answer:

14

Step-by-step explanation:

72° = 8persons

360° =???

\frac{360 \times 8}{72}  = 40persons \\

Total number of candidates in kevals sch = 40

Number that achieved grade A is

360° = 40persons

126° =???

\frac{126 \times 40}{360}  = 14persons

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Point U is on line segment TV . given TU=4 UV=5x and TV=3x+6 determine the numerical lenth of TV
adelina 88 [10]

TU=13; UV= 13; TV=26

Step-by-step explanation:

Hope this helped!

6 0
3 years ago
Read 2 more answers
Experian would like to test the hypothesis that the average credit score for an adult in Virginia is different from the average
aliya0001 [1]

Answer:

a. We fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

b. The 95% confidence interval for the true difference of means is -2.2468 and 36.2468. There is a probability of 95% that the true difference of means \mu_{1}-\mu_{2} is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

Step-by-step explanation:

Let \mu_{1}-\mu_{2} be the true difference between the average credit score for an adult in Virginia and the average credit score for an adult in North Carolina. We have the large sample sizes n_{1} = 40 and n_{2} = 35, the unbiased point estimate for \mu_{1}-\mu_{2} is \bar{x}_{1} - \bar{x}_{2}, i.e., 699-682 = 17.

The standard error is given by \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}, i.e.,

\sqrt{\frac{(44)^{2}}{40}+\frac{(41)^{2}}{35}} = 9.8198.

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative). The rejection region is given by RR = {z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles of the standard normal distribution respectively. The test statistic is Z = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}} and the observed value is z_{0} = \frac{17}{9.8198} = 1.7312. Because 1.7312 does not fall inside RR, we fail to reject the null hypothesis.

b. The endpoints for a 95% confidence interval for \mu_{1}-\mu_{2} is given by 17\pm (z_{0.05/2})9.8198, i.e., 17\pm (z_{0.025})9.8198 where z_{0.025} is the 2.5th quantile of the standard normal distribution, i.e., -1.96, so, we have 17-(1.96)(9.8198) and 17+(1.96)(9.8198), i.e., -2.2468 and 36.2468. There is a probability of 95% that the true difference of means \mu_{1}-\mu_{2} is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

3 0
3 years ago
Austin and Dale earn money by painting fences over the summer. Working alone, Austin takes 3 hours longer than Dale to paint a f
mojhsa [17]

Answer:

Austin will take 9 hours to paint a room and dale with take 3 hours to paint a room

Step-by-step explanation:

3 0
3 years ago
Felicia drew a triangle with side lengths that measured 15 cm, 18 cm and 27 cm. To determine if Felicia drew a right triangle, s
Charra [1.4K]

Answer:

The equation should be h²=P²+b²

27²=15²+18²

729=225+324

729=549

thus, it is not right angle triangle

3 0
3 years ago
Please help me solve this whole problem!
Dvinal [7]
I’m not good at math srry but hope someone answers the is for you
3 0
2 years ago
Read 2 more answers
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