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levacccp [35]
3 years ago
8

The varsity soccer team has 20 players. Three of the players are trained to be goalies while the remaining 17 can play any posit

ion. Only 11 players can be on the field at once. The coach wants to make sure there is exactly one goalie on the field. How many ways can the coach choose a lineup of 11 players if exactly 1 player must be a goalie
Mathematics
1 answer:
Vadim26 [7]3 years ago
6 0

Answer:

The coach can choose a lineup of 11 players in 6,047,981,701,347 different ways.

Step-by-step explanation:

Since the varsity soccer team has 20 players, and three of the players are trained to be goalies while the remaining 17 can play any position, and only 11 players can be on the field at once, and the coach wants to make sure there is exactly one goalie on the field, to determine how many ways can the coach choose a lineup of 11 players if exactly 1 player must be a goalie the following calculation has to be made:  

3 x 17 ^ 10 = X

3 x 2,015,993,900,449 = X

6,047,981,701,347 = X

Therefore, the coach can choose a lineup of 11 players in 6,047,981,701,347 different ways.

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Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
~.❤~Please Answer~❤.~
Verizon [17]

Answer:

True

hope it helps!

Step-by-step explanation:

3 0
3 years ago
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Could someone help me on this?
timama [110]
The snswer is B lol get smarter
6 0
1 year ago
Read 2 more answers
What operation do you use to convert 50 cups to gallons?
zzz [600]
Division can be used. For example

50/16=3.125gallons

or you could use multiplication

50*1/16=3.125gallons


5 0
3 years ago
Read 2 more answers
How many centimeters are there in 1/5 of an inch
Lynna [10]

Answer:

0.508

Step-by-step explanation:

4 0
3 years ago
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