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2 years ago

Find the value: 3/2 ÷ 5/8 (write your answer as a fraction AND as a decimal number)

Mathematics

2 answers:

DanielleElmas [232]2 years ago

6 0

3 5

/ ÷ /

2 8

To solve this, the first step would be to make the reciprocal of 5 / 8 which is 8 / 5, then change the division sign to a multiplication sign.

3 8

/ x /

2 5

3 x 8 = 24

2 x 5 = 10

24 / 10 = 12 / 5 or 2 2/5

12 divided by 5 = 2.4

Ahhhh sorry i misread it the first time and flipped the wrong equation

Vikki [24]2 years ago

4 0

Answer:

Decimal : 2.4

Fraction: 2 4/10 or 2 2/5

Step-by-step explanation:

hope this helps :) plz mark brainliest to help my rank

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How many of these pitchers can a cylinder with height 9 inches and 2r fill? Explain how you know.

irakobra [83]

Answer:

4 pitches

Step-by-step explanation:

if a cylinder with height 9 inches and radius r is filled with water, it can fill a certain pitcher. how many of these pitchers can a cylinder with height 9 inches and radius 2r fill? explain how you know.

Solution:

The volume of a cylinder is given by:

V = πr²h;

where V is the volume, r is the radius of the cylinder and h is the height of the cylinder.

A cylinder with height 9 inches and radius r can fill a certain pitcher. Therefore the volume of the cylinder is:

V = πr²h = πr²(9) = 9πr²

V = volume of pitcher = volume of cylinder with radius r = 9πr²

For a cylinder with height 9 inches and radius 2r its volume is:

V2 = πr²h = π(2r)²(9) = 36πr²

Therefore, the number of pitchers a cylinder with height 9 inches and radius 2r can fill is:

number of pitches = 36πr² / 9πr² = 4

Therefore a cylinder with height 9 inches and radius 2r can fill 4 pitches.

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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2 years ago

PLEASE HELP 30 POINTS!!!!!!!!!!!!!!!!!!!!!!!

Anettt [7]

Since you know the value of "x", you can plug in the value for "x" in the equation.

[When an exponent is negative, you move it to the other side of the fraction to make the exponent positive.]

For example:

$x^{-2}$ or $\frac{x^{-2}}{1} =\frac{1}{x^2}$

$\frac{1}{y^{-3}} =\frac{y^3}{1}$ or y³

x = -2

f(x) = 9x + 7

f(-2) = 9(-2) + 7 = -18 + 7 = -11

$g(x)=5^x$

$g(-2)=5^{-2}=\frac{1}{5^2}=\frac{1}{25}$ (idk if you should have it as a decimal or a fraction)

x = -1

f(x) = 9x + 7

f(-1) = 9(-1) + 7 = -9 + 7 = -2

$g(x)=5^x$

$g(-1)=5^{-1}=\frac{1}{5}$

x = 0

f(x) = 9x + 7

f(0) = 9(0) + 7 = 7

$g(x)=5^x$

$g(0)=5^0=1$

x = 1

f(x) = 9x + 7

f(1) = 9(1) + 7 = 9 + 7 = 16

$g(x)=5^x$

$g(1)=5^1=5$

x = 2

f(x) = 9x + 7

f(2) = 9(2) + 7 = 18 + 7 = 25

$g(x)=5^x$

$g(2)=5^2=25$

You need to determine the solution of f(x) = g(x)

Since you know f(x) = 9x + 7 and $g(x)=5^x$ , you can plug in (9x + 7) for f(x), and ( $5^x$ ) into g(x)

f(x) = g(x)

$9x+7=5^x$ You can plug in each value of x into the equation

Your answer is x = 2 because when you plug in 2 for x in the equation, you get 25 = 25

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2 years ago