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lana [24]
3 years ago
12

A security administrator wants to empty the DNS cache after a suspected attack that may have corrupted the DNS server. The serve

r has been repaired, however it is feared that DNS entries may remain in client computer caches. Which of the following tools can be used to flush the DNS cache on a Windows client?
a. NET
b. PING
c. NSLOOKUP
d. IPCONFIG
Computers and Technology
1 answer:
mario62 [17]3 years ago
3 0

Answer: (D) IPCONFIG

Explanation:

The IPCONFIG is the type of tool that can be use to flush or refresh the dynamic host configuration (DNS) cache on the window client. The IPCONFIG display various types of parameters such as subnet mask, IP address and the default gateway.

 In the computing, the IPCONFIG is stand for the internet protocol configuration and it is one of the operating system applications which basically display all Transmission control protocol/ Internet protocol (TCP/IP) network configurations.

Therefore,Option (D) is correct.

 

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What is personal data

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Explanation:

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Human centered technology often recommends a0 to computer designers and manufacturers, telling them how to make systems and the
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Human centered technology often recommends best practices to computer designers and manufacturers, ...............

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No multiple choice?
4 0
3 years ago
Convert infix to postfix
kvv77 [185]

Answer:

static int checkSymbol(char ch)

{

switch (ch)

{

case '+':

case '-':

return 1;

case '*':

case '/':

return 2;

case '^':

return 3;

}

return -1;

}

static String convertInfixToPostfix(String expression)

{

String calculation = new String("");

Stack<Character> operands = new Stack<>();

Stack<Character> operators = new Stack<>();

 

for (int i = 0; i<expression.length(); ++i)

{

char c = expression.charAt(i);

if (Character.isLetterOrDigit(c))

operands.push(c);

else if (c == '(')

operators.push(c);

 

else if (c == ')')

{

while (!operators.isEmpty() && operators.peek() != '(')

operands.push(operators.pop());

 

if (!operators.isEmpty() && operators.peek() != '(')

return NULL;    

else

operators.pop();

}

else

{

while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))

operands.push(operators.pop());

operators.push(c);

}

}

while (!operators.isEmpty())

operands.push(operators.pop());

while (!operands.isEmpty())

calculation+=operands.pop();

calculation=calculation.reverse();

return calculation;

}

Explanation:

  • Create the checkSymbol function to see what symbol is being passed to the stack.
  • Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
  • Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
  • While the operators is  not empty, keep pushing the character to the operators stack.
  • At last reverse and return the calculation which has all the results.
4 0
3 years ago
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