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4 years ago

1. Zayn surveyed a group of people about how many times they ate at a

1 answer:

3 0

Mean: 11
Median: 9
Mode: 7

Mean is when you add up all of the numbers, then you take the sum you get and divide by the amount of numbers you have. So in this case, it’d be 154 (the sum) divided by 14 (the amount of numbers you have).
Median is when you put all of your numbers in ascending order and then find the middle number. In this case, the amount of numbers we had were even, so the middle numbers were 8 and 10. In between of these two numbers, is the number 9. So as a result, 9 is your answer.
Mode is the number that you see the most in a set of number. In this case, 7 is repeated 3 times, unlike other numbers, which happens to be the most. So, 7 is your answer for the mode.

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3 years ago

A random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength

irinina [24]

Answer:

Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.

Step-by-step explanation:

We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.

Let $\bar X$ = sample mean comprehensive strength

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean comprehensive strength = 5500 psi

$\sigma$ = standard deviation = 100 psi

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P( $\bar X$ > 4985 psi)

P( $\bar X$ > 4985 psi) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{4985-5500}{\frac{100}{\sqrt{9} } }$ ) = P(Z > -15.45) = P(Z < 15.45)

= 0.99999

Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.

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4 years ago

Draw three circles with centre 0 and the radii of 3cm, 5cm and 7cm respectively

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Ummm 48 cm ima be honest I need some points my fault

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3 years ago

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I’m pretty sure it’s the second one if not I’m so sorry

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3 years ago

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saul85 [17]

Answer:

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Step-by-step explanation:

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3 years ago