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yarga [219]
3 years ago
14

It is estimated 30% of all adults in United States invest in stocks and that 84% of U.S. adults have investments in fixed

Mathematics
1 answer:
lana66690 [7]3 years ago
6 0

Answer:

=109%

Step-by-step explanation:

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Solve the measurement conversion problem. 1 km = 1,000m Add all amounts then convert
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Answer:

The answer is C.) In order to get one kilometer, you have to have 1,000 meters.

Step-by-step explanation:

Hope this helped.

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Write the equation for the vertical line that passes through the point (5,-2)
amid [387]

If it's just a vertical line, then it could be displayed as: x = 5.

A vertical line is not actually a function, and because of such, the entire line is just the value of the x value, as it will never have enough x value.


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3 years ago
Which graph fits y=2x+1?
alekssr [168]

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C

Step-by-step explanation:

4 0
3 years ago
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On a certain day the exchange rate was 60 u.s dollars 50 euro. How many US dollars were 70 euro worth that day? Show that your a
gayaneshka [121]
This is what I got:

60/50 = X/70
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8 0
3 years ago
Suppose that 15% of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in t
hram777 [196]

Answer:

a.\mu=15

b.\mu=7.8586 \ and  \ \mu=22.1414

c. Choice A- Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

Step-by-step explanation:

a.Binomial distribution is defined by the expression

P(X=k)=C_k^n.p^k.(1-p)^{n-k}

Let n be the number of trials,n=100

and p be the probability of success,p=15\%

The mean of a binomial distribution is the probability x sample size.

\mu=np=100\times0.15=15

b.Limits within which p is approximately 95%

sd of a binomial distribution is given as:\sigma=\sqrt npq\\q=1-p

Therefore, \sigma=\sqrt(100\times0.015\times0.85)=3.5707

Use the empirical rule to find the limits. From the rule, approximately 95% of the observations are within to standard deviations from mean.

sd_1=>\mu-2\sigma=15-2\times3.3507=7.8586\\sd_2=>\mu-2\sigma=15+2\times3.3507=22.1414

Hence, approximately 95% of the observations are within 7.8586 and 22.1414 (areas of infestation).

c.  x=45 is not within the limits in b above (7.8586,22.1414). X=45 appears to be a large area of infestation. A.Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

4 0
4 years ago
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