A) > since it is 50c per weekday and 75c each weekend assuming it allows for the 2 days each saturday/sunday.
50c * 5 = $2.50 since there are 5 days in weekdays
75c * 2 = $1.50 since there are 2 days in the weekend
Add $2.50 and $1.50 to get $4.00
b) For 3 school days we know it is a weekday on the school week.
So perform 50c * 3 which gives us <span>$1.50
</span>c) 12 days off from school is 10 weekdays and 1 weekend or 2 days of 75c
So now just do 50c * 10 which is $5.00 and 75c * 2 which is $1.50
Add $5.00 and $1.50 and we get $6.50
d) 4 weeks = 20 weekdays since 5 *4 = 20 and 8 days in each weekend since 2 * 4 = 8
Now that we have the amount of weekdays and weekend days we can multiply.
50c * 20 = $10.00
75c * 4 = $3.00
Add $10.00 and $3.00 to get $13.00 for 4 weeks.
e) We have 1 day of the weekend and 2 weekdays here.
50c * 2 = $1.00
75c * 1 = 75c
<span>$1.00 + 75c = $1.75 in those 3 days listed.
</span>
Add all these together to get your total value.
$4.00 + $1.50 + $6.50 + $13.00 + $1.75 = $26.75
Answer:
It is true.
Step-by-step explanation:
congruent polygons have the exact same size and are a perfect match because all corresponding parts are congruent (equal). ... This means that if two polygons are similar, then their corresponding angles are congruent
Its asking how much did they both spent, in total, in order to reach the same amount spent in part A
Answer:
Distance = 7
Step-by-step explanation:
![d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\d= \sqrt{(5-(-2))^2+(2-2)^2} \\d= \sqrt{(7)^2+(0)^2} \\d= \sqrt{49+0} \\d= \sqrt{49}\\ d= 7](https://tex.z-dn.net/?f=d%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%20%5C%5Cd%3D%20%5Csqrt%7B%285-%28-2%29%29%5E2%2B%282-2%29%5E2%7D%20%5C%5Cd%3D%20%5Csqrt%7B%287%29%5E2%2B%280%29%5E2%7D%20%5C%5Cd%3D%20%5Csqrt%7B49%2B0%7D%20%5C%5Cd%3D%20%5Csqrt%7B49%7D%5C%5C%20d%3D%207)