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3 years ago

What plus what would equal 3744

Mathematics

2 answers:

larisa [96]3 years ago

6 0

To figure out other questions like this dived you number by 2

Murrr4er [49]3 years ago

4 0

1872 + 1872

answers have to be more than 20 characters to post so um..

ELRIS COMEBACK 26/02

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What is the probability annie does not choose a girl who is a junior

ICE Princess25 [194]

A every every low chance

8 0

3 years ago

Read 2 more answers

After the 15% sales tax the jeans were $11.50. How much was the jeans before the sales price?

agasfer [191]

Thirteen dollars and twenty two cents just add 15% to $11.50.

8 0

3 years ago

Which expression is equivalent and why?

Ivenika [448]

9514 1404 393

Answer:

C. 1.15x

Step-by-step explanation:

You are given the expression for the cost:

x + 0.15x

Combining like terms, this becomes ...

1.15x . . . . . matches choice C

3 0

3 years ago

A survey of high school juniors found the 75% of the students plan on attending college. If you pick 3 students at random, what

olya-2409 [2.1K]

Assuming you pick 3 students at random, The probability that at least two plan on attending college is 84%.

<h3>Probability</h3>

Using Binomial Distribution

Given:

n = 3

p = 0.75

q = 1-0.95 = 0.25

Hence:

P[≥2] = P[2] + P[3]=(3c2 ×0.75²×0.25) + 0.75³

P[≥2] = P[2] + P[3]=0.421875+0.421875

P[≥2] = P[2] + P[3]=0.84375×100

P[≥2] = P[2] + P[3]=84% (Approximately)

Inconclusion the probability that at least two plan on attending college is 84%.

Learn more about probability here:brainly.com/question/24756209

4 0

2 years ago

The distribution of prices for home sales in a certain New Jersey county is skewed to the right with a mean of $290,000 and a st

I am Lyosha [343]

Answer:

The probability that the mean of the sample is greater than $325,000

$P( X > 3,25,000) = P( Z >2.413) = 0.008$

Step-by-step explanation:

Step(i):-

Given the mean of the Population( )= $290,000

Standard deviation of the Population = $145,000

Given the size of the sample 'n' = 100

Given 'X⁻' be a random variable in Normal distribution

Let X⁻ = 325,000

$Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{325000-290000}{\frac{145000}{\sqrt{100} } } = 2.413$

Step(ii):-

The probability that the mean of the sample is greater than $325,000

$P( X > 3,25,000) = P( Z >2.413)$

= 0.5 - A(2.413)

= 0.5 - 0.4920

= 0.008

Final answer:-

The probability that the mean of the sample is greater than $325,000

$P( X > 3,25,000) = P( Z >2.413) = 0.008$

6 0

3 years ago