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bija089 [108]
3 years ago
7

After last week's victory, he bought 2 medium pizzas and 1 large pizza, which is the perfect amount for the 9 players that got t

o come. This week, there were 33 players going, so he ordered 4 medium pizzas and 5 large pizzas, which was also the perfect amount of pizza needed. How many people does each size pizza feed?
Mathematics
1 answer:
Fynjy0 [20]3 years ago
8 0

Answer:

Kahoot: The Emoji Quiz

Meet: wff-qjue-fja

DONT WORRY IM NOT A OLD MAN

PLSDHQGH.

Step-by-step explanation:

You might be interested in
Describe the range of a square root function
Ket [755]
Range of square root function is from [0, infinity)
6 0
3 years ago
Use the quadratic regression to find the equation for the parabola going through these 3 points (-5, 161) (-2, 29) (6, 205)
Rama09 [41]

Answer:

The equation of the parabola is y = 6x^{2}-2b+1

Step-by-step explanation:

First we write a quadratic equation of parabola as y = ax^{2}+bx+c

Now it is given in the question that parabola passes through three points (-5,161),(-2,29),(6,205).

To find the equation we have to get the value of a,b & c.

Now we form three equations to find the value of a,b,c.

We put the value (-5,161) in the equation

161 = a×25+b×(-5)+c

161 = 25a-5b+c----------(1)

Now we put (-2,29) in the equation

29 = a×4+b×(-2)+c

29 = 4a-2b+c---------(2)

Again we put (6,205) in the equation

205 = a×36+6b+c------------(3)

Now we subtract equation (1) from (2)

161-29 = 25a-4a-5b-(-2b)+c-c

132 = 21a-5b+2b

132 = 21a-3b

132 = 3(7a-b)

44 = 7a-b---------(4)

Now we subtract equation (2) from (3)

205-29 = 36a-4a+6b-(-2b)+c-c

176 = 32a+6b+2b

176 = 32a+8b

176 = 8(4a+b)

22 = 4a+b------------(5)

Now we add equation (5) and (4)

44+22 = 7a+4a-b+b

66 = 11a

a = 6

Now we put the value a in equation (4)

44 = 7×6-b

44 = 42-b

44-42 = -b

2 = (-b)

b = (-2)

Now we put the value of a and b in equation number (2)

29 = 4×6-2(-2)+c

29 = 24+4+c

29 = 28+c

c = 29-28

c =1

Finally we put the value of a,b,c in the quadratic equation

y = 6x^{2}+(-2)x+1

y = 6x^{2}-2+1

This is the final answer.

6 0
3 years ago
If a tree casts a shadow of 25ft at the same time that a 4ft person casts a shadow of 11 1/2 ft, find the height of the tree?
Sunny_sXe [5.5K]
<h3>Answer:</h3>

8.70 ft

<h3>Step-by-step explanation:</h3>

We are given;

  • Shadow of a tree as 25 ft
  • Height of a person as 4ft
  • Shadow of the person as 11.5 ft

We are required to determine the height of the tree

<h3>Step 1: Find the angle of elevation from the tip of the shadow to the top of the person.</h3>

tan θ = opp/adj

In this case; Opposite side = 4 ft

                    Adjacent side = 11.5 ft

Therefore; tan θ = (4 ft ÷ 11.5 ft)

                  tan θ = 0.3478

                        θ  = tan⁻¹ 0.3478

                       θ  = 19.18°

<h3>Step 2: Calculate the height of the tree</h3>

The angle of elevation from the tip of the shadow of the tree to the top of the tree will 19.18°

Therefore;

Opposite = Height of the tree

Adjacent = 25 ft

Thus;

tan 19.18 ° = x/25 ft

     x = tan 19.18° × 25 ft

        = 0.3478 × 25 ft

        = 8.695

       = 8.70 ft

Therefore, the height of the tree is 8.70 ft

6 0
3 years ago
Solve for a, if F= w/9a <br> need step by step explanation
Law Incorporation [45]

Answer:

a=w/9F

Step-by-step explanation:

First multiply 9a to F to have 2 equations equal each other. Divide 9aF by 9F to get a on it’s own.

Steps clear down below

8 0
3 years ago
Use the image above to identify and explain the relationship between the segments and circles A and B. In your explanation, be s
Sergio [31]

Answer:

Step-by-step explanation:

From the given figure, it can be seen that there are two circles with centers A and B respectively. The circle with the center A is larger in size than the circle with center B. Points P, Q and E lie on the surface of the circle having center A and R, S, C and T points lie on the circle having center B.

One tangent passes from the point  Q of the one circle to the point T of the another circle and the other tangent passes from point R of the smaller circle to the point E of the larger circle. These two tangents intersects each other outside both the circle. There is another tangent which passes from the point C of the smaller circle to a point D lying outside the circle.

3 0
3 years ago
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