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Nikolay [14]
3 years ago
9

Describe the sequence of transformations that demonstrates the congruence between triangle ABC and triangle A´B´C´.

Mathematics
1 answer:
Shtirlitz [24]3 years ago
4 0

Reflecting over the x axis means to perform the following tranformation:

(x,y) \to (x,-y)

So, you maintain the x coordinate, and change the sign of the y coordinate. The vertices become

A=(-4, 4)\to \hat{A} = (-4,-4),\quad B=(-2, 3)\to \hat{B} = (-2,-3),\quad C=(0, 7) \to \hat{C}=(0,-7)

Translating 3 units to the left means to perform the following transformation:

(x,y) \to (x-3,y)

So, you maintain the y coordinate, and decrease the x coordinate by 3. The vertices become

\hat{A} = (-4,-4) \to (-7,-4),\quad \hat{B} = (-2,-3)\to (-5,-3),\quad \hat{C}=(0,-7)\to (-3,-7)

So, as you can see, after these two transformation, the vertices A, B and C become A', B' and C'.

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PLEASE HELP!!!
Vinvika [58]
He started off with 99$
if u take the reciprocal of each fraction
22(3/2) = 33
then 33(3/1) = 99
as a check 99(2/3) is 66 and 66(1/3) = 22 which is what he is left with
8 0
3 years ago
Read 2 more answers
(10) Does the table show a proportional relationship?
Blababa [14]

Answer:

No

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Determine a polynomial that represents the area of the parallelogram.<br> A=
sp2606 [1]

Answer:

4b² - 16

Step-by-step explanation:

The formula to find the area of a parallelogram equals bh, where b = base and h - height. We're given the base as 2b + 4 and the height as 2b - 4.

  • (2b+4)*(2b-4)=(2b+4)(2b-4)
  • (2b+4)(2b-4)=(2b)(2b)+(2b)(-4)+(4)(2b)+(4)(-4)
  • 4b^2-8b+8b-16
  • 4b^2-16

Therefore, the answer is 4b² - 16.

6 0
2 years ago
Two friends sold many pieces of furniture and made ​$1550 during their garage sale. They had fifteen more​ $10 bills than​ $50 b
Novosadov [1.4K]

Answer:

The number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

Step-by-step explanation:

Let n₁ = number of $ 10 bills,

Let n₂ = number of $ 20 bills and

Let n₃ = number of $ 50 bills

Given that 10n₁ + 20n₂ + 50n₃ = 1550    (1)

Also, since we have fifteen more​ $10 bills than​ $50 bills, n₁ = n₃ + 15  (2)

and we have 4 more than three times as many​ $20 bills as​ $50 bills. n₃ = 3n₂ + 4. (3)

substituting equations (2) and (3) into (1), we have

10(n₃ + 15) + 20n₂ + 50n₃ = 1550

expanding the bracket, we have

10n₃ + 150 + 20n₂ + 50n₃ = 1550

collecting like terms, we have

60n₃ + 150 + 20n₂ = 1550

inserting equation (3), we have

60(3n₂ + 4) + 150 + 20n₂ = 1550

expanding the bracket, we have

180n₂ + 240 + 150 + 20n₂ = 1550

collecting like terms, we have

200n₂ + 390 = 1550

subtracting 390 from both sides, we have

200n₂ = 1550 - 390

200n₂ = 1160

dividing both sides by 200, we have

n₂ = 1160/200

n₂ = 5.8

n₂ ≅ 6 since it cannot be a fraction.

Substituting this into (3), we have

n₃ = 3n₂ + 4 = 3(6) + 4 = 18 + 4 = 22

substituting n₃ into (2), we have

n₁ = n₃ + 15 = 22 + 15 = 37

So, the number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

3 0
3 years ago
The product of a number and 16 is equal to the sum of the number and 14​
nevsk [136]

Step-by-step explanation:

let number be x

16x = 14 + x

16x - x = 14

15x = 14

x = 14 ÷ 15

x = 0.9

7 0
2 years ago
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