Which ordered pairs are on the line 2x−3y=8 ? Select each correct answer. (12,−73) (−2,4) (2,−43) (−5,−6)
2 answers:
Answer:
Option D is correct.
(-5, -6)
Step-by-step explanation:
Ordered pair states that a pair of number that is locate a point on a coordinate plane i.,e (x, y)
Given the line: .....[1]
Option A:
(12, -73)
Substitute the value of x = 12 and y = -73 in [1] we have;
2(12) - 3(-73) = 8
24 + 219 = 8
243 = 8 False.
Similarly for;
Option B
(-2, 4)
2(-2) - 3(4) = 8
-4 -12 = 8
-20 = 8 False.
Option C
(2, 43)
2(2) - 3(43) = 8
4-129= 8
-125= 8 False.
Option D
(-5, -6)
2(-5) - 3(-6) = 8
-10 +18 = 8
8 = 8 True.
Therefore, only (-5, -6) ordered pair is on the line 2x-3y = 8
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Answer:
Square root of 4 is 2
so 1+=4
frac{[1+sqrt{2x-1]}^2 }{4}=3
so 1+sqrt{2x-1]}^2=12
so 1+sqrt{2x-1}=V12
sqrt{2x-1}=V12-1
2x-1=(V12-1)^2=12-2V12+1=13-2V12
2x=13+1-2V12
2x=14-2V12
x=7-V12
x=7-2V3
I put an attachment to explain better
Step-by-step explanation:
