9514 1404 393
Answer:
P = 3x +32
Step-by-step explanation:
If we assume the short vertical edge at top center is 10 yards, as it was in two previous problems with this geometry, then we can find the area of the present parking lot as ...
(x-2)(3x) + x(3x -10) +2x(40) = 6x^2 +64x
where the left vertical rectangle is 3x high and x-2 wide; the center area between vertical rectangles is (2x-2)-(x-2) = x wide and (3x-10) high; and the right vertical rectangle is (x-2 +3x)-(2x-2) = 2x wide and 40 high.
As we said, the right vertical rectangle is 2x wide, so the area that has P as one of its dimensions is ...
A = LW = P(2x)
We want this to be the same as the existing area, so ...
2Px = 6x^2 +64x
P = 3x +32 . . . . . divide by 2x
Answer:
y=-9
Step-by-step explanation:
slope intercept form: y=mx+b, m being the slope
y=6 times -3
since there isn't a y intercept, you can't really put it in standard form unless I missed a step.
y= -9
Answer:
c. 1 3/20
Step-by-step explanation:
a guess hopefully you are right
1. Add -4.5 to 18.5
2. Divide 23 by 7
3. Then subtract 6 from -2.7
Answer:
6
Step-by-step explanation:
3 x 2 = 6
OR
3 + 3 = 6
:)