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grin007 [14]
2 years ago
5

a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th

at 3 or less (P (x <= 3) are blemished?
Mathematics
1 answer:
hodyreva [135]2 years ago
6 0

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in ^{5000}C_{10} ways.

Possibility 1: <u>3 tires are blemished.</u>

Total 10 tires can be chosen with 3 blemished tires in ^{1000}C_3 \times {4000}C_7 ways.

Possibility 2:  <u>2 tires are blemished.</u>

Total 10 tires can be chosen with 2 blemished tires in ^{1000}C_2 \times ^{4000}C_8  ways.

Possibility 3: <u>1 tires are blemished.</u>

Total 10 tires can be chosen with 1 blemished tires in ^{1000}C_1 \times^{4000}C_9 ways.

Possibility 4:  <u>No tires are blemished.</u>

Total 10 tires can be chosen with no blemished tires in ^{1000}C_0 \times^{4000}C_{10} ways.

Hence, the required probability is \frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }.

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A regular pentagon has an apothem of 7.3 inches and a perimeter of 53 inches. What is the area of the pentagon? Round your answe
zvonat [6]

Answer:

Area pf the regular pentagon is 193inch^{2} to the nearest whole number

Step-by-step explanation:

In this question, we are tasked with calculating the area of a regular pentagon, given the apothem and the perimeter

Mathematically, the area of a regular pentagon given the apothem and the perimeter can be calculated using the formula below;

Area of regular pentagon = 1/2 × apothem × perimeter

From the question, we can identify that the value of the apothem is 7.3 inches, while the value of the perimeter is 53 inches

We plug these values into the equation above to get;

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3 years ago
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Answer:

4/1/7 ( 4 and 1 over 7)

Step-by-step explanation:

First add all the numbers

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I believe you should try to plug in the ordered pair to see if the solutions work.

The ordered pair is (x,y) because x is on the x-axis and y is on the y-axis, therefore in (16,-3) the x=16 and y=-3.

Now substitute, meaning plug in those numbers into the equation.
For x+2y=10 would be 16+2(-3)=10
Now you just need to solve one side and see if it equals the other side.
16+2(-3)
First you use order of operations to solve this. PEMDAS. So you multiply 2(-3) first because of the parenthesis and it being multiplication.
16+(-6) and when you have a positive number adding a negative number it’s going backwards of the number line, basically meaning subtraction in a way. Sorry if this confuses you, if you already know how to do negatives and such nevermind this part.
But 16+(-6)=10
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Now for the next equation, 7y=-21
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There is no x in this equation so no need to worry about that; you only plug in y for this one.
7(-3) Now you multiply. Whenever you multiply a positive number and a negative number, the answer will always be negative. So 7(-3) is -21.
Now look if the left side is equivalent to the right. Does -21=-21? Yes. The ordered pair is a solution.

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