Answer: not sure
but I need points
Step-by-step explanation:
JUST KIDDING It’s A I did this in school before and got it correct :)
Any value you choose for x will make the equation a TRUE statement. This type of equation is called an identity, and the solution set is all real numbers.
Answer:
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Step-by-step explanation:
given that acceleration vector is a funciton of time and at time t

v(t) can be obtained by integrating a(t)
v(t) = 
Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.
The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)
Position vector can be obtained by integrating v(t)
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)