Answer:
The answer to your question is: x = 15 and y = 17
Step-by-step explanation:
∠A = 6x
∠B = 9y - 63
they are linear pair, their addition gives 180°
but it also mention that linear pair with equal measure, so each angle measures 90°
6x = 90
x = 90/6
x = 15
9y - 63 = 90
9y = 90 + 63
9y = 153
y = 153/9
y = 17
5 pounds- $17.50
1 pound- $17.50 divide by 5 pounds then multiple 1 pound=$3.50
10 pounds- $35
15 pounds- $52.50
20 pounds-$70
25 pounds- $87.50
30 pounds-$105
To get an average score of 80% (out of four exams), a total of 4*80%=320% is needed, so the minimum required for the 4th test is 320-(75+97+60)=88.
To get an average score of 89% (out of four exams), a total of 4*89%=356% is needed, so the maximum required for the 4th test is 356-(75+97+60)=124, which is impossible.
So the next exam grade must range between 88 and 100 to get a grade b in the class.
Hoped I help! Mark brainly it would help<3
Answer:
There were 6 benches in park 1 and 18 benches in park 2.
Step-by-step explanation:
Let x be the no of benches in Park 1 and y in park 2.
Given that there are 12 more benches in park 2 than 1
Writing this in equation form, we have y = x+12 ... i
Next is if 2 benches were transferred from park 2 to park 1, then we have
x+2 in park 1 and y-2 in park 2.
Given that y-2 = twice that of x+2
Or y-2 = 2x+4 ... ii
Rewrite by adding 2 to both sides of equation ii.
y = 2x+6 ... iii
i-iii gives 0 = -x+6
Or x =6
Substitute in i, to have y = 6+12 = 18
Verify:
Original benches 6 and 18.
18 = 6+12 hence I condition is satisfied
18-2 = 2(6+2)
II is also satisfied.
