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4 years ago

Question: (5x-8)/(45x^2--42x-48)

Mathematics

2 answers:

Vladimir79 [104]4 years ago

7 0

Answer:

Step-by-step explanation:

9x+6

Edge 2020

My name is Ann [436]4 years ago

4 0

To solve this problem you must apply the proccedure shown below:

1. You have the folllowing expression given in the problem above:

$(5x-8)/(45x^{2}-42x-48)$

2. The first thing you must do is to factor the denominator, as following:

$(5x-8)/3(3x+2)(5x-8)$

3. Now, simplify it and apply the distributive property in the denominator:

$1/3(3x+2)=1/9x+6$

The answer is: $1/9x+6$

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Soloha48 [4]

Answer:

Latoya's statement because they are similar not congruent

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2 years ago

Can someone pls explain this?

ryzh [129]

Answer:

A piecewise function.

Step-by-step explanation:

The problem you showed is a piecewise function.

In this problem, you have to plug in 3 for the value x.

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Way to check this input is undefined:

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According to the definition of a function, a function can have many inputs but only one output. In this case, this function has one input, that is 3, but produces two outputs.

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2 years ago

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Y_Kistochka [10]

Answer: Table A

Step-by-step explanation:

The coefficient of x^2 is 1, the coefficient of x is -6, and the constant is 0. This means that a = 1, b = -6, and c = 0.

This eliminates tables B and C.

Now, we need to determine if the graph opens up or down to differentiate between A and B. Since the coefficient of x^2 is positive, the graph opens up.

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7 0

2 years ago

When the solutions are going to be complex, which methods can be used to solve quadratic equations?

yKpoI14uk [10]

You could complete the square to state the vertex.
You could use the quadratic equation to find the roots (which are complex).

Try an example that will require both.

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Step One
Get the graph. That's included below.

Step Two
Provide the steps for completing the square.
Note: we should get (-1,4)

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y = (x^2 +2x + 1) + 5 - 1
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The vertex is at (-1,4)

Step Three
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$\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}$

a = 1
b = 2
c = 5

$\text{x = }\dfrac{ -2 \pm \sqrt{2^{2} - 4*1*5 } }{2}$
$\text{x = }\dfrac{ -2 \pm \sqrt{4 - 20 } }{2}$
$\text{x = }\dfrac{ -2 \pm \sqrt{-16 } }{2}$
$\text{x = }\dfrac{ -2 \pm 4i }{2}$
x = -1 +/- 2i

x1 = -1 + 2i
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