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blagie [28]
4 years ago
10

Which compound contains both ionic and covalent bonds? 1) potassium chloride 2) potassium hydride 3) potassium nitrate 4) potass

ium oxide
Chemistry
2 answers:
Lunna [17]4 years ago
7 0

Answer:

Potassium nitrate

Explanation:

Because NO3 (nitrate) consists of 4 covalently bonds atom. NO3, incorporate of nitrate which share electrons then Ionic bonding occurred between K(as cation) NO3(as anion).

klio [65]4 years ago
6 0

Answer: 3) potassium nitrate

Explanation:

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and forms a positively charged ion called as cation. The element which accepts the electrons is known as electronegative element and forms a negatively charged ion called as anion.

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

1.  potassium chloride :KCl is made up of ionic bond between metal and non metal.

2.  potassium hydride :KH is made up of ionic bond between metal and non metal.

3) potassium nitrate : KNO_3 made up of ionic bond and NO_3 is made up of covalent bond between two non metals nitrogen and oxygen.

4) potassium oxide: K_2O is made up of ionic bond between metal and non metal.

Thus potassium nitrate contains both ionic and covalent bonds.

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alexira [117]

Answer:

a) The pH of the solution is 12.13.

b) The pH of the solution is 12.17.

Explanation:

Ionic product of water =K_w=1.01\times 10^-{14}

K_w=[H^+][OH^-]

1.01\times 10^-{14}=[H^+][OH^-]

Taking negative logarithm on both sides:

-\log[1.01\times 10^-{14}]=(-\log [H^+])+(-\log [OH^-])

The pH is the negative logarithm of hydrogen ion concentration in solution.

The pOH is the negative logarithm of hydroxide ion concentration in solution.

13.99=pH+pOH

a) 1.39\times 10^{-2} M of NaOH.

Concentration of hydroxide ions:

NaOH(aq)\rightarrow Na^+(aq)+OH^-(aq)

So, [OH^-]=1\times [NaOH]=1\times 1.39\times 10^{-2} M=1.39\times 10^{-2} M

pOH=-\log[1.39\times 10^{-2} M]=1.86

13.99=pH+pOH

13.99=pH+1.86

pH=13.99-1.86=12.13

b) 0.0051 M of NaOH.

Concentration of hydroxide ions:

Al(OH)_3(aq)\rightarrow Al^{3+}(aq)+3OH^-(aq)

So, [OH^-]=3\times [Al(OH)_3]=3\times 0.0051 M=0.0153 M

pOH=-\log[0.0153 M]=1.82

13.99=pH+pOH

13.99=pH+1.82

pH=13.99-1.82=12.17

6 0
3 years ago
Identify oxidation.
nevsk [136]

Oxidation is "Increase in oxidation number" as well as loss of electrons.

A rise in oxidation number results from the loss of negative electrons, whereas a reduction in oxidation number results from the gain of electrons. As a consequence, the oxidized element or ion experiences a rise in oxidation number.

As a result of losing electrons in the process, a reactant oxidizes. When a reactant obtains electrons during a reaction, reduction takes place. This frequently happens when acid and metals react.

Therefore, Oxidation is "Increase in oxidation number" as well as loss of electrons.

Hence, the correct answer will be option (e)

To know more about Oxidation

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