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Furkat [3]
2 years ago
11

How do weak intermolecular bond strengths affect the melting and boiling point of a substance?

Chemistry
1 answer:
kobusy [5.1K]2 years ago
3 0

Answer:

both melting point and boiling points are lower

this is because it becomes easier to break those bonds (they’re actually intermolecular forces) between the atoms sinc they’re weak, and thus require less energy to break.

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It’s Neptune hehe :))
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3 years ago
Read 2 more answers
Calculate the hydronium ion concentration in an aqueous solution with a poh of 4.33 at 25°c.
Jlenok [28]

Taking into account the definition of pH and pOH, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

<h3>Definition of pH</h3>

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or  hydronium ion H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

<h3>Definition of pOH</h3>

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

<h3>Relationship between pH and pOH</h3>

The following relationship can be established between pH and pOH:

pOH + pH= 14

<h3>Concentration of hydronium ions</h3>

Being pOH= 4.33, pH is calculated as:

pH + 4.33= 14

pH= 14 - 4.33

<u><em>pH= 9.67</em></u>

Replacing in the definition of pH the concentration of hydronium ions is obtained:

- log [H₃O⁺]= 9.67

Solving:

[H₃O⁺]= 10⁻⁹ ⁶⁷

<u><em>[H₃O⁺]= 2.138×10⁻¹⁰ M</em></u>

Finally, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

Learn more about pH and pOH:

brainly.com/question/16032912

brainly.com/question/13557815

#SPJ1

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2 years ago
In July 1928, Calouste Gulbenkian, the Anglo-Persian Oil Company, Standard
kramer

Answer:

The correct answer is A: Anglo Standard Shell Conglomerate

Explanation:

8 0
3 years ago
What is the total number of oxygen atoms on the left-hand side of this chemical equation?
Dennis_Churaev [7]

Answer:

Is the answer eight atoms

6 0
3 years ago
2.14g of sodium sulfide react with excess hydrochloric acid to form sodium chloride and dihydrogen sulfide.
hichkok12 [17]

Answer:

2.14 Na2S + 1.99 HCl ----> 3.20 NaCl + 0.935 H2S

Explanation:

The Balanced equation is

Na2S + 2HCl = 2NaCl + H2S

As we can see -

78.0452 g/mol of sodium sulfide reacts with 2 mole of HCl.

Mass of one mole of HCl = 36.458 g/mol

So, 78.0452 g/mol of sodium sulfide reacts with 2* 36.458 g/mol of HCL to produce 2* 58.44 g of NaCl and 34.1 g/mol of H2S

Thus,

2.14g of sodium sulfide will react with (2* 36.458/78.0452)* 2.14 of HCl

2.14g of sodium sulfide will react with 1.99 g of HCl

2.14 Na2S + 1.99 HCl ----> (2* 58.44/78.0452) *2.14 NaCl + (34.1/78.0452) * 2.14 H2S

2.14 Na2S + 1.99 HCl ----> 3.20 NaCl + 0.935 H2S

4 0
3 years ago
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