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Furkat [3]
2 years ago
11

How do weak intermolecular bond strengths affect the melting and boiling point of a substance?

Chemistry
1 answer:
kobusy [5.1K]2 years ago
3 0

Answer:

both melting point and boiling points are lower

this is because it becomes easier to break those bonds (they’re actually intermolecular forces) between the atoms sinc they’re weak, and thus require less energy to break.

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Work out the volume of 0.1 moles of chlorine gas at room temperature and pressure.
Lilit [14]

Volume of gas at room temperature = number of moles x 24 dm^3

Volume = 0.1 moles x 24 dm^3

Volume = 2.4 dm^3  (or 2400 cm^3)

5 0
4 years ago
What happen to the size of balloon if it is gone to upward direction ?​
natima [27]

Answer:

nothing happens

Explanation:

this just means that the density is lower than the air

3 0
3 years ago
If 27.50 mL of 0.120 M NaOH neutralizes 0.248 g of HAA, what is the molar mass of unknown amino acid
tino4ka555 [31]

Answer:

75.15 g/mol

Explanation:

First, let us look at the equation of reaction;

NaOH + HAA --> NaAA + H_2O

From the balanced equation of reaction, 1 mole of NaOH is required to completely neutralize 1 mole of HAA.

Recall that: mole = molarity x volume.

Therefore, 27.50 mL, 0.120 M NaOH = 0.0275 x 0.120 = 0.0033 moles

0.0033 mole of NaOH will therefore requires 0.0033 moles of HAA for complete neutralization.

In order to find the molar mass of the unknown amino acid, recall that:

<em>mole = mass/molar mass</em>, hence, <em>molar mass = mass/mole</em>.

Therefore, molar mass of HAA = 0.248/0.0033 = 75.15 g/mol

6 0
3 years ago
What are the properties of the aluminum in the can? Check all that apply.
vladimir2022 [97]

Answer:

It is solid

Explanation:

Well a can i hard and solid because it is metal

8 0
3 years ago
How many ATOMS of boron are present in 3.61 grams of boron trifluoride ?
Delvig [45]

Hi there!

\large\boxed{3.203 *  10^{22} atoms}

We can use the following conversions to solve:

Total mass --> amount of mols --> amount of atoms (Avogadro's number)

Begin by calculating the amount of boron trifluoride in 3.61 grams:

3.61 g * (1 mol BF₃ / 67.8 g) ≈ 0.0532 mol BF₃

Use avogadro's number to convert:

0.0532 mol * 6.02× 10²³atoms / 1 mol = 3.203 × 10²² atoms

3 0
3 years ago
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