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zaharov [31]
3 years ago
9

I will give you branilest!

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

You are correct, and you could also write an expression where m = money, p = people, and v = vehicle

m · p · v = ___

I hope this helps you ^‿^

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Please answer correctly! I will Mark you as Brainliest!
rosijanka [135]

Answer:

the answer is 40.5!

Step-by-step explanation:

First, you have to add all of the numbers up!

7 0
3 years ago
A package of 16 individual bags of Takis cost $12.80. If each bag contains 12 ounces, what is the unit cost per ounce?
Gnom [1K]

Answer:

$0.067

Step-by-step explanation:

Total cost of 16 bags = $12.80

weight in 1 bag = 12 ounce

weight in 16 bag = 16 * weight in 1 bag

weight in 16 bag = 16* 12 ounce = 192 ounce

Thus,

192 ounce cost = Total cost of 16 bags= $12.80

cost of 182 ounce = $12.80

to find cost of 1 ounce , we divide both side by 182

cost of 1 ounce = 12.80/192 = $0.067

Thus,

the unit cost per ounce is $0.067

5 0
3 years ago
Need help please make sure your right people have been saying wrong answers​
sweet [91]

Answer:

C

Step-by-step explanation:

Trust me, take the square root of 24, which divides into 2 x 2 x 2 x 3, and you pull a pair of 2 out, left inside a 6

7 0
3 years ago
Read 2 more answers
What is the opposite integer of 6
kotykmax [81]
It would be negative six.
3 0
3 years ago
(Partially Done!) Verify the identity and show your work.
vladimir1956 [14]
Throughout all of these steps I'm only going to alter the left hand side (LHS). I am NOT going to change the right hand side (RHS) at all.

Before I change the LHS of the original equation, let's focus on the given identity
cot^2(x) + 1 = csc^2(x)

Since we know it's an identity, we can subtract 1 from both sides and the identity would still hold true
cot^2(x) + 1 = csc^2(x)
cot^2(x) + 1-1 = csc^2(x)-1
cot^2(x) + 0 = csc^2(x)-1
cot^2(x) = csc^2(x)-1

So we'll use the identity cot^2(x) = csc^2(x)-1

---------------------------------------------

Now onto the main equation given

cot^2(x) + csc^2(x) = 2csc^2(x) - 1
cot^2(x) + csc^2(x) = 2csc^2(x) - 1 .... note the term in bold
csc^2(x)-1 + csc^2(x) = 2csc^2(x) - 1 .... note the terms in bold
[ csc^2(x) + csc^2(x) ] - 1 = 2csc^2(x) - 1
[ 2csc^2(x) ] - 1 = 2csc^2(x) - 1
2csc^2(x) - 1 = 2csc^2(x) - 1

The bold terms indicate how the replacements occur.

So the original equation has been proven to be an identity because the LHS has been altered to transform into the RHS
7 0
3 years ago
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