If you have 3/5 marbles and you got 4/3more marbles then all you have to do is:3/5 x 3/3 and get 9/15.For 4/3 you multiply 4/3 x 5/5 and get 20/15.You simplify this and get 1 5/15.Now all you do is add them and get 1 14/15. Hope this helped you :-).
Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.
Answer:
2(y+5)
Step-by-step explanation:
= 2y+10 simple multiplication method
First one single solution second no solution 3rd one single forth one infinity and last 2 are single and infinity
The midpoint, if the endpoints are (x₁,y₁) and (x₂,y₂):


The midpoint of AB is (4,3).