The scale factor in the question given above is: 2 See the explanation below.
<h3>What is a scale factor?</h3>
In math, the scale factor is the extent or ratio by which a geometrical shape is enlarged or reduced.
<h3>What is the explanation for the above answer?</h3>
We know that:
- The distance from point Q to point A is 1.25
- The distance from point A to point A' is 1.25
Given the above, the distance from point Q to point A' is 2.50. This is double the distance from point Q to point A.
The scale factor is 2.
1.25 + 1.25 = 2.50
2.50 / 1.25 = 2
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For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
We can use the formula y2-y1/x2-x1 to find our answer. So, we have : t-16/5-2 = -3. We simplify that to t-16/3 = -3. We can then multiply both sides by 3 to get t-16 = -9. Then we can add 16 to both sides to get t = 7.
10 different groups can ski.
This is a combination of 5 items taken 3 at a time: