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mylen [45]
3 years ago
15

This project involves writing a program that encodes and decodes messages. The program should prompt the user to select whether

a message is to be encoded or decoded, and then prompts the user to enter the message. A blank space is used to separate each word in the message, and a period (.) is used to denote the end of a sentence. Separate methods must be used to encode and decode the input message. The coding scheme is very simple: the code
Computers and Technology
1 answer:
Lilit [14]3 years ago
8 0

Answer:

See explaination

Explanation:

import java.util.Scanner;

public class EncodeDecodeMessage {

public static String encode(String str) {

String result = "";

char ch;

for(int i = 0; i < str.length(); ++i) {

ch = str.charAt(i);

if(Character.isLowerCase(ch)) {

result += (char)('a' + (25-ch+'a'));

} else if(Character.isUpperCase(ch)) {

result += (char)('A' + (25-ch+'A'));

} else {

result += ch;

}

}

return result;

}

public static String decode(String str) {

return encode(str); // since the scheme is same, we can use encode for decode

}

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

System.out.print("1. Encode, 2. Decode. Enter your choice: ");

int choice = in.nextInt();

in.nextLine();

if(choice == 1) {

System.out.print("Enter sentence to encode: ");

String line = in.nextLine();

System.out.println("Encoded string is: " + encode(line));

} else if(choice == 2) {

System.out.print("Enter sentence to decode: ");

String line = in.nextLine();

System.out.println("Decoded string is: " + decode(line));

}

}

}

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Write a program that asks the user to enter a number of seconds. There are 60 seconds in a minute. If the number of seconds ente
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Answer:

// here is code in c.

#include <stdio.h>

// main function

int main()

{

// variable to store seconds

long long int second;

printf("enter seconds:");

// read the seconds

scanf("%lld",&second);

// if seconds is in between 60 and 3600

if(second>=60&& second<3600)

{

// find the minutes

int min=second/60;

printf("there are %d minutes in %lld seconds.",min,second);

}

// if seconds is in between 3600 and 86400

else if(second>=3600&&second<86400)

{

// find the hours

int hours=second/3600;

printf("there are %d minutes in %lld seconds.",hours,second);

}

// if seconds is greater than 86400

else if(second>86400)

{

// find the days

int days=second/86400;

printf("there are %d minutes in %lld seconds.",days,second);

}

return 0;

}

Explanation:

Read the seconds from user.If the seconds is in between 60 and 3600 then find the minutes by dividing seconds with 60 and print it.If seconds if in between 3600 and 86400 then find the hours by dividing second with 3600 and print it. If the seconds is greater than 86400 then find the days by dividing it with 86400 and print it.

Output:

enter seconds:89

there are 1 minutes in 89 seconds.

enter seconds:890000

there are 10 days in 890000 seconds.

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