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gogolik [260]
3 years ago
6

I need to send this in ASAP

Computers and Technology
2 answers:
maria [59]3 years ago
6 0
The first one is an ampersat or more commonly known as an at symbol that is typically used to mention or forward someone something as an address sign.
The second one is percent (a percentage symbol) that is commonly used in mathematics to indicate a ratio out of 100.
The third one is an asterisk that is used to indicate an omission or use in writing and printing as a reference mark.
The fourth, the last one is an octothorope also called a number sign or pound sign that may signify numbers over the phone or used to classify/categorize accompanying text like in social media as a hashtag.
NISA [10]3 years ago
5 0

Answer:

YES

EYES

Answer:

YES

EYES

Answer:

YES

EYES

Answer:

YES

EYES

Answer:

YES

EYES

Answer:

YES

EYES

Answer:

YES

EYES

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(Financial application: compound value) Suppose you save $100 each month into savings account with an annual interest rate of 5%
Nostrana [21]

Solution:

initial = float(eval(input('Enter the monthly saving amount: ')))

x = (1 + 0.00417)

month_one = initial * x

month_two = (initial + month_one) * x  

month_three = (initial + month_two) * x  

month_four = (initial + month_three) * x

month_five = (initial + month_four) * x  

month_six = (initial + month_five) * x  

print('The sixth month value is: '+str(month_six))  

Don't forget the saving amount, and initialize the balance with that amount. Inside the loop, work out and add the interest and then add the saving amount for the next month.

balance = 801

for month in range(6):

  balance = balance * (1.00417)

print(balance)

7 0
3 years ago
A software-based _________ is dedicated to examining and blocking internet traffic.
igomit [66]

A software-based <u>Firewall</u> is dedicated to examining and blocking internet traffic.

7 0
3 years ago
Read 2 more answers
Write a Java class to perform the following: 1. Write a method to search the following array using a linear search, ( target ele
Alina [70]

Answer:

Check the explanation

Explanation:

Linear search in JAVA:-

import java.util.Scanner;

class linearsearch

{

  public static void main(String args[])

  {

     int count, number, item, arr[];

     

     Scanner console = new Scanner(System.in);

     System.out.println("Enter numbers:");

     number = console.nextInt();

   

     arr = new int[number];

     System.out.println("Enter " + number + " ");

     

     for (count = 0; count < number; count++)

       arr[count] = console.nextInt();

     System.out.println("Enter search value:");

     item = console.nextInt();

     for (count = 0; count < number; count++)

     {

        if (arr[count] == item)

        {

          System.out.println(item+" present at "+(count+1));

         

          break;

        }

     }

     if (count == number)

       System.out.println(item + " doesn't found in array.");

  }

}

Kindly check the first attached image below for the code output.

Selection Sort in JAVA:-

public class selectionsort {

   public static void selectionsort(int[] array){

       for (int i = 0; i < array.length - 1; i++)

       {

           int ind = i;

           for (int j = i + 1; j < array.length; j++){

               if (array[j] < array[ind]){

                   ind = j;

               }

           }

           int smaller_number = array[ind];  

           array[ind] = array[i];

           array[i] = smaller_number;

       }

   }

     

   public static void main(String a[]){

       int[] arr = {9,94,4,2,43,18,32,12};

       System.out.println("Before Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

       System.out.println();

         

       selectionsort(arr);

       

       System.out.println("After Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

   }

}  

Kindly check the second attached image below for the code output.

Bubble Sort in JAVA:-

public class bubblesort {

   static void bubblesort(int[] array) {

       int num = array.length;

       int temp = 0;

        for(int i=0; i < num; i++){

                for(int j=1; j < (num-i); j++){

                         if(array[j-1] > array[j]){

                           

                                temp = array[j-1];

                                array[j-1] = array[j];

                                array[j] = temp;

                        }

                         

                }

        }

   }

   public static void main(String[] args) {

               int arr1[] ={3333,60,25,32,55,620,85};

               

               System.out.println("Before Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

               System.out.println();

                 

               bubblesort(arr1);

               

               System.out.println("After Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

 

       }

}  

Kindly check the third attached image below for the code output.

Binary search in JAVA:-

public class binarysearch {

  public int binarySearch(int[] array, int x) {

     return binarySearch(array, x, 0, array.length - 1);

  }

  private int binarySearch(int[ ] arr, int x,

        int lw, int hg) {

     if (lw > hg) return -1;

     int middle = (lw + hg)/2;

     if (arr[middle] == x) return middle;

     else if (arr[middle] < x)

        return binarySearch(arr, x, middle+1, hg);

     else

        return binarySearch(arr, x, lw, middle-1);

  }

  public static void main(String[] args) {

     binarysearch obj = new binarysearch();

     int[] ar =

       { 22, 18,12,14,36,59,74,98,41,23,

        34,50,45,49,31,53,74,56,57,80,

        61,68,37,12,58,79,904,56,99};

     for (int i = 0; i < ar.length; i++)

        System.out.print(obj.binarySearch(ar,

           ar[i]) + " ");

     System.out.println();

     System.out.print(obj.binarySearch(ar,19) +" ");

     System.out.print(obj.binarySearch(ar,25)+" ");

     System.out.print(obj.binarySearch(ar,82)+" ");

     System.out.print(obj.binarySearch(ar,19)+" ");

     System.out.println();

  }

}

Kindly check the fourth attached image below for the code output

7 0
3 years ago
Identify the menu under which you'll find the Header and Footer option.
Genrish500 [490]

The answer is B. View.

4 0
3 years ago
The Mohs scale is used to express which mineral property?
olchik [2.2K]
Its answer is c. hardness

5 0
3 years ago
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