Answer: A) It is directly accessible only in B1
Explanation: In the given chunk of code, Class B1 is a base class. Class B2 is derived class of class B1. Class B3 is derived class of B2. As you can see class B1 has two members or instance variables i and j. Instance variable cannot be directly accessible by both B2 and B3. If you see this statement of the given code private int j; the keyword private is used with the variable j. This keyword is called access specifier. Access specifiers specifies how the members of a class can be accessed. These members are attributes and methods of that class. Any member of a class that are declared private cannot be inherited by derived classes of that class. Additionally these private members cannot be accessed from within any method inside derived class. So j is directly accessible only in B1. You can access a private instance variable from within the same class or can access it through the methods of class.
I believe the answer is Virtual Private Network (VPN).
Know this answer is late, but im doing my deed hoping i this can help someone else pass this darn class. Best of Luck to whoever is taking the same course. You can do it if my lazy self can do it! It'll be okay ;)
Answer:
#include<iostream>
using namespace std;
int lcm(int m, int n) {
int a;
a = (m > n) ? m: n;
while (true) {
if (a % m == 0 && a % n == 0)
return a;
++a;
}
}
int gcd(int m, int n) {
int r = 0, a, b;
a = (m > n) ? m : n;
b = (m < n) ? m : n;
r = b;
while (a % b != 0) {
r = a % b;
a = b;
b = r;
}
return r;
}
int main(int argc, char **argv) {
cout << "Enter the two numbers: ";
int m, n;
cin >> m >> n;
cout << "The LCM of two numbers is: " << lcm(m, n) << endl;
cout << "The GCD of two numbers is: " << gcd(m, n) << endl;
return 0;
}
Explanation:
