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mr_godi [17]
3 years ago
8

Hello hello helppppppppppppp

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
7 0
Answer:
5 units left and 2 units down
olganol [36]3 years ago
6 0

Answer:

the person anove is correct

Step-by-step explanation:

You might be interested in
Given MO is perpendicular to NP and NO is congruent to PO prove MN is congruent to MP
VladimirAG [237]
Lets imagine the shape 
M
  /\
  / | \
  / | \
  / | \
  P /___ |___\ N
  O
 Now in If we take â†MOP and â†MON
 As MO ⊥ NP so â MON=â MOP
 NO=NP (given)
 And MO is a common side 
 so by side angle side rule of congruency 
 â†MOP and â†MON are congruent
 so MP is congruent to MN
8 0
4 years ago
What is k if : k!+48=48((k+1)^m)
lys-0071 [83]

Answer:

The value of k is greater than or equal to 0, i.e. k≥7.

Step-by-step explanation:

The given equation is

k!+48=48((k+1)^m)

The value of k must be a positive integer because k! is defined for k≥0, where k∈Z.

Subtract 48 from both the sides.

k!=48((k+1)^m)-48

k!=48((k+1)^m-1)

k!=48(k+1-1)(\frac{(k+1)^m-1}{(k+1)-1})

Using [\frac{r^m-1}{r-1}=r^{m-1}+r^{m-2}+...+1], we get

k!=48k((k+1)^{m-1}+(k+1)^{m-2}+...+1)

Divide both sides by 48k.

\frac{k!}{48k}=(k+1)^{m-1}+(k+1)^{m-2}+...+1

\frac{k(k-1)!}{48k}=(k+1)^{m-1}+(k+1)^{m-2}+...+1

\frac{(k-1)!}{48}=(k+1)^{m-1}+(k+1)^{m-2}+...+1

Note: The value of m can be 0 or 1.

The value of k is positive integer, so the right hand side of the above equation must be a positive integer.

Since RHS of the equation is positive integer, therefore (k-1)! is completely divisible by 48.

k-1\geq 6

Add 1 on both sides.

k\geq 6+1

k\geq 7

Therefore the value of k is greater than or equal to 0.

4 0
4 years ago
A survey by the state health department found that the average person ate 208 pounds of vegetables last year and 125 5/8 pounds
jonny [76]

Answer: The fraction of pounds of fruits over total pounds of fruits and vegetables is given by

\frac{25125}{66724}

Step-by-step explanation:

Since we have given that

Total amount of vegetables = 208 pounds

Total amount of fruits is given by

125\frac{5}{8}\text{ pounds}

Total amount of fruits and vegetables is given by

208+125\frac{5}{8}\\\\=208+\frac{1005}{8}\\\\=\frac{1664+1005}{8}\\\\=\frac{2669}{8}\\\\=333.625\text{ pounds }

So, we need to find the fraction of pounds of fruits over the total pounds of fruit and vegetables :

\frac{\text{Pounds of fruits }}{\text{ total pounds of fruits and vegetables}}\\\\=\frac{\frac{1005}{8}}{333.62}\\\\=\frac{1005}{8\times 333.62}\\\\=\frac{1005}{2668.96}=\frac{25125}{66724}

3 0
3 years ago
What is 42789 x 54678
vichka [17]
42789 times 54678
is 2,339,616,942

Show Work:
<span>Calculate 9 x 8, which is 72.
Since 72 is two-digit, we carry the first digit 7 to the next column.
</span>
3 <span>Calculate 8 x 8, which is 64. Now add the carry digit of 7, which is 71.
Since 71 is two-digit, we carry the first digit 7 to the next column.
</span>
4 <span>Calculate 7 x 8, which is 56. Now add the carry digit of 7, which is 63.
Since 63 is two-digit, we carry the first digit 6 to the next column.
</span>

5 <span>Calculate 2 x 8, which is 16. Now add the carry digit of 6, which is 22.
Since 22 is two-digit, we carry the first digit 2 to the next column.
</span>
6 <span>Calculate 4 x 8, which is 32. Now add the carry digit of 2, which is 34.
Since 34 is two-digit, we carry the first digit 3 to the next column.
</span>
7 <span>Bring down the carry digit of 3.
</span>
8 <span>Calculate 9 x 7, which is 63.
Since 63 is two-digit, we carry the first digit 6 to the next column.
</span>
9 <span>Calculate 8 x 7, which is 56. Now add the carry digit of 6, which is 62.
Since 62 is two-digit, we carry the first digit 6 to the next column.
</span>
10 <span>Calculate 7 x 7, which is 49. Now add the carry digit of 6, which is 55.
Since 55 is two-digit, we carry the first digit 5 to the next column.
</span>
11 <span>Calculate 2 x 7, which is 14. Now add the carry digit of 5, which is 19.
Since 19 is two-digit, we carry the first digit 1 to the next column.
</span>
12 <span>Calculate 4 x 7, which is 28. Now add the carry digit of 1, which is 29.
Since 29 is two-digit, we carry the first digit 2 to the next column.
</span>

13 <span>Bring down the carry digit of 2.
</span>
14 <span>Calculate 9 x 6, which is 54.
Since 54 is two-digit, we carry the first digit 5 to the next column.
</span>
15 <span>Calculate 8 x 6, which is 48. Now add the carry digit of 5, which is 53.
Since 53 is two-digit, we carry the first digit 5 to the next column.
</span>

16 <span>Calculate 7 x 6, which is 42. Now add the carry digit of 5, which is 47.
Since 47 is two-digit, we carry the first digit 4 to the next column.
</span>

17 <span>Calculate 2 x 6, which is 12. Now add the carry digit of 4, which is 16.
Since 16 is two-digit, we carry the first digit 1 to the next column.
</span>

18 <span>Calculate 4 x 6, which is 24. Now add the carry digit of 1, which is 25.
Since 25 is two-digit, we carry the first digit 2 to the next column.
</span>

19 <span>Bring down the carry digit of 2.
</span>

20 <span>Calculate 9 x 4, which is 36.
Since 36 is two-digit, we carry the first digit 3 to the next column.
</span>
21 <span>Calculate 8 x 4, which is 32. Now add the carry digit of 3, which is 35.
Since 35 is two-digit, we carry the first digit 3 to the next column.
</span>
22 <span>Calculate 7 x 4, which is 28. Now add the carry digit of 3, which is 31.
Since 31 is two-digit, we carry the first digit 3 to the next column.
</span>
23 <span>Calculate 2 x 4, which is 8. Now add the carry digit of 3, which is 11.
Since 11 is two-digit, we carry the first digit 1 to the next column.
</span>
24 <span>Calculate 4 x 4, which is 16. Now add the carry digit of 1, which is 17.
Since 17 is two-digit, we carry the first digit 1 to the next column.
</span>
25 <span>Bring down the carry digit of 1.
</span>
26 <span>Calculate 9 x 5, which is 45.
Since 45 is two-digit, we carry the first digit 4 to the next column.
</span>
27 <span>Calculate 8 x 5, which is 40. Now add the carry digit of 4, which is 44.
Since 44 is two-digit, we carry the first digit 4 to the next column.
</span>
28 <span>Calculate 7 x 5, which is 35. Now add the carry digit of 4, which is 39.
Since 39 is two-digit, we carry the first digit 3 to the next column.
</span>
29 <span>Calculate 2 x 5, which is 10. Now add the carry digit of 3, which is 13.
Since 13 is two-digit, we carry the first digit 1 to the next column.
</span>
30 <span>Calculate 4 x 5, which is 20. Now add the carry digit of 1, which is 21.
Since 21 is two-digit, we carry the first digit 2 to the next column.
</span>
31 <span>Bring down the carry digit of 2.
</span>
32 <span>Calculate 342312 + 2995230 + 25673400 + 171156000 + 2139450000, which is 2339616942</span>
<span>         </span>
6 0
3 years ago
Read 2 more answers
−2 2 21 +(−0.25÷(− 1 4 )−1.5÷(− 3 16 ))÷(−4 1 11 )
Setler79 [48]

Answer:

-2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})=-4.0551

Step-by-step explanation:

Given : Expression -2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})  

To find : Simplify the expression ?

Solution :

Using BODMAS,

-2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})  

=-\frac{44}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-\frac{45}{11})

=-\frac{44}{21}+(\frac{0.25}{14}+\frac{1.5\times 16}{3})\div(-\frac{45}{11})

=-\frac{44}{21}+(\frac{0.25}{14}+\frac{24}{3})\div(-\frac{45}{11})

=-\frac{44}{21}+(\frac{0.25\times 3+24\times 14}{14\times 3})\div(-\frac{45}{11})

=-\frac{44}{21}+(\frac{336.75}{42})\div(-\frac{45}{11})

=-\frac{44}{21}-\frac{336.75\times 11}{42\times 45}

=-\frac{44}{21}-\frac{3704.25}{1890}

=\frac{-44\times 1890-3704.25\times 21}{21\times 1890}

=\frac{-160949.25}{39690}

=−4.0551

Therefore, -2\frac{2}{21}+(-0.25\div(-14)-1.5\div(-\frac{3}{16}))\div(-4\frac{1}{11})=-4.0551

6 0
4 years ago
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