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bearhunter [10]
3 years ago
6

Steve placed 5 weights on a scale during science class. If each weight

Mathematics
1 answer:
s2008m [1.1K]3 years ago
3 0

Answer:

4

Step-by-step explanation:

If each weight is the same than we can simple multiply the weight of one by the number of weights there are

5(0.8)=4

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If f(1) = 2 and f(n) = –2f(n − 1) then find the value of f(5).
dybincka [34]

Answer: 2f

Explanation:

f(1)=8

f(2)= 2(8) = 16

f(3) = 2(16) = 32

f(4) = 2(32) = 64

f(5) = 2(64) =128

6 0
3 years ago
How many solutions does the following equation have?<br><br> 3x + 6 = 3(x + 2)
kow [346]
3x+6=3(x+2)
3x+6=3x+6
minus 6 both sides
3x=3x
divide by 3
x=x

true

therefor all numbers work for x

there are infinite soltuions
8 0
3 years ago
1/4( 16x-8)-8x= -1/3 ( ? x+9)
MatroZZZ [7]

Answer:

d.16

Step-by-step explanation:

3 0
3 years ago
HELP I dont understand-
Naddik [55]

Step-by-step explanation:

If a radius of a circle and a tangent to a circle intersect at the point of tangency, then the radius and the tangent are perpendicular.

Answer: B

8 0
3 years ago
Read 2 more answers
tickets were sold at four different gates. Gate D sold 24%. Gate A sold 36%. Gate C sold 14%. Gate B sold 26%. If 39 tickets wer
Drupady [299]

Answer:

150 tickets

Step-by-step explanation:

Given: Tickets sold at four different gates

           Gate B sold 26 % tickets

           Tickets sold at Gate B = 39

Let take x as total number of tickets sold at all four gates.

Now, using the value of gate B to find total number of tickets

∴ 26\% \times total\ ticket\ sold = 39

⇒ \frac{26}{100} \times x = 39

Next, cross multiply both side

⇒ x= \frac{39\times 100}{26} = 150\ tickets

∴ Total tickets sold at all the four gates is 150

5 0
4 years ago
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