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lidiya [134]
4 years ago
11

How to solve rational equation:

Mathematics
1 answer:
Zina [86]4 years ago
8 0
Like when adding/subtracting fractions at any other time, you need a common denominator, in this case (x-1)(x+1)=x^2-1 so:

(2(x+1)+3(x-1))/(x^2-1)=4  multiply both sides by (x^2-1)

2x+2+3x-3=4x^2-4  combine like terms on left

5x-1=4x^2-4  subtract (5x-1) from both sides

4x^2-5x-3=0 using the quadratic formula for expediency

x=(5±√73)/8

x≈-0.443 and 1.693
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Find the directional derivative of f(x,y,z)=z3−x2yf(x,y,z)=z3−x2y at the point (−5,5,2)(−5,5,2) in the direction of the vector v
olga_2 [115]

We are given

f=z^3 -x^2y

Firstly, we can find gradient

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f_x=0 -2xy

f_x=-2xy

f_y=0 -x^2

f_y=-x^2

f_z=3z^2

now, we can plug point (-5,5,2)

f_x=-2*-5*5=50

f_y=-(-5)^2=-25

f_z=3(2)^2=12

so, gradient will be

gradf=(50,-25,12)

now, we are given that

it is in direction of v=⟨−3,2,−4⟩

so, we will find it's unit vector

|v|=\sqrt{(-3)^2+(2)^2+(-4)^2}

|v|=\sqrt{29}

now, we can find unit vector

v'=(\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

now, we can find dot product to find direction of the vector

dir=(gradf) \cdot (v')

now, we can plug values

dir=(50,-25,12) \cdot (\frac{-3}{\sqrt{29} } , \frac{2}{\sqrt{29} } , \frac{-4}{\sqrt{29} })

dir=(-\frac{150}{\sqrt{29} } - \frac{50}{\sqrt{29} } - \frac{48}{\sqrt{29} })

dir=-\frac{248\sqrt{29}}{29}.............Answer



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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
An angle measures 150° more than the measure of its supplementary angle. What is the measure of each angle?
madreJ [45]

Answer:

<h2>          165°  and  15°</h2>

Step-by-step explanation:

x      - an angle

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