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Molodets [167]
3 years ago
14

At an assessment 7 out of the first 10 students where the first to enter the gym were carrying a backpack. Based on the informat

ion, if 700 students were at the assembly, how many students could be expected to be carrying a backpack?
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
4 0
The answer is 490 because 70% is the 7 out 10 students
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5/9

Step-by-step explanation:

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tigry1 [53]

<u>Answer:</u>

x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i are two roots of equation -3 x^{2}-x-3=0

<u>Solution:</u>

Need to solve given equation using quadratic formula.

-3 x^{2}-x-3=0

General form of quadratic equation is a x^{2}+b x+c=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}

Since b^{2}-4 a c is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}

8 0
4 years ago
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GenaCL600 [577]

Answer:

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Step-by-step explanation:

8                  10

16                 20

24                  30

32                   40              

40


8 0
3 years ago
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elena-14-01-66 [18.8K]

Answer:

? = 1

Step-by-step explanation:

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