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Ahat [919]
3 years ago
6

HELP Please!!!

Mathematics
2 answers:
daser333 [38]3 years ago
8 0

Answer:

1. false

2. false

3. true

Step-by-step explanation:

1. If the value of a was negative, then the graph of the quadratic would open downwards because the negative sign would induce a reflection of the graph over the x-axis.

However, we can see from the graph that the quadratic opens up, so a is not negative and this statement is false.

2. The vertex of a quadratic equation is the minimum or maximum point. Here, since the graph points up, the vertex will be the minimum point. That point is actually (3, -1). Clearly, this is not (-1, 3), so the statement is false.

3. The axis of symmetry is essentially the line with the x-value of the vertex. Since the x-coordinate of the vertex is 3, that means the axis of symmetry is the line x = 3. Thus, the statement is true.

scoray [572]3 years ago
4 0

Answer:

False

False

True

Step-by-step explanation:

Since it's a concave up, a > 0

Vertex: (3,-1)

Symmetry: x = 3

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Calculate the straight line distance between the points (-10, -7) and (-8,1).<br> G.2(B)
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Step-by-step explanation:

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We can use the distance formula. Recall that:

\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Substitute and evaluate:

\displaystyle \begin{aligned} d &= \sqrt{((-10)-(-8))^2 + ((-7) - (1))^2} \\ \\ &=\sqrt{(-2)^2+(-8)^2} \\ \\ &= \sqrt{(4) + (64)} \\ \\ &= \sqrt{68}\\ \\ &= 2\sqrt{17}\end{aligned}

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