Answer:
{-3, 2}U{2, 5}
Step-by-step explanation:
For an equation to be negative, it would need to be in a negative range (below the x-axis or the coordinates are negative y-values). Therefore, we can examine this question and see that the graph is negative when the function crosses the x-axis at -3 and it remains negative until you reach 2 on the x-axis.
Therefore, the first set of negative values is (-3, 2).
Secondly, applying the same logic as before, the function decreases at 2 and then touches the x-axis again at 5. Therefore, the second negative value would be (2, 5).
The negative values are {-3, 2}U{2, 5}.
Step-by-step explanation:
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behaviour
Select one:
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b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
= Power___is the capacity to influence
behaviour
Select one:
a. Self-interest
b. Coercion
c. Power
d. Potential
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c. Power
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Answer: No. Equations even if it is paired. So on. It can only have one solution. Although this is only for a system of equations.
A linear can have two. It just depends on what the problem is.
Step-by-step explanation:
I think it would be a triangle, because they said it would be cut at an angle.
We have system:
y=2x+1
y=2x^2+1
To find which ordered pair is solution to this system we need to solve system for x and y.
Left sides are same so the right sides must be same too.
2x+1=2x^2+1
2x-2x^2+1-1=0
2x-2x^2=0
2x(1-x)=0
x1=0
x2=1
y1=2*0+1=1
y2=2*1+1=3
The solution are pairs (0,1) and (1,3).
