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dexar [7]
3 years ago
7

⚠️⚠️24 points⚠️⚠️

Mathematics
2 answers:
Irina-Kira [14]3 years ago
4 0

Answer:

im assumming no?

Step-by-step explanation:


motikmotik3 years ago
3 0

Answer: No. Equations even if it is paired. So on. It can only have one solution. Although this is only for a system of equations.

A linear can have two. It just depends on what the problem is.


Step-by-step explanation:


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Anna35 [415]

Answer:

Hi ma bruddah

Step-by-step explanation:

Hi - ma - bru/dd/ah

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2 years ago
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X/3 - 38 =42 what is the value of x
madam [21]
X/3 - 38 = 42

x/3 = 80

x = 240
8 0
3 years ago
The perimeter of a standard football field,including end zone is 1040 feet. if the field is 360 feet long,how wide is the field
ozzi
360 * 2=720
1049-720=320
320/2=110 so the answer is it is 110 ft wide

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3 years ago
To discourage guessing on the multiple-choice exam a professor assigned 4 points for a correct answer, -4 points for an incorrec
Zanzabum

Answer:

35

Step-by-step explanation:

4 x 15 = 60

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8 0
3 years ago
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A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

7 0
3 years ago
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