All categories

4 years ago

A student solved an equation and got the answer 3=9 how many solutions dose the equation have?

Mathematics

1 answer:

Nady [450]4 years ago

3 0

Answer:

No solutions, 0

Step-by-step explanation:

When you solve a equation and get an answer of n = s (I am just using n and s a placeholders. They that be any number.) where n ≠ s, then there are no solutions to the equation.

You might be interested in

You are planning to purchase displays for your store which has 2400 sq ft of selling space. each display has a footprint of 10ft

polet [3.4K]

For this case, the sales space of the displays is given by:
(2400) * (1-0.60) = 960 feet ^ 2
We now look for the area of each display:
(10) * (4) = 40 feet ^ 2
With this information, we can then search the number of displays:
N = (960) / (40)
N = 24 displays
Answer:
you can fit 24 displays.

5 0

3 years ago

John earned $36 for 8 hours of work, Earnings are directly proportional with hours worked. How much did he earn when he worked 3

ahrayia [7]

Answer:

he earned 135 dolars

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Can someone please help me!!!! I’ll mark you brainiest if the answer is correct

Anna [14]

Answer:

A is 210

B is volume

C is surface area

8 0

3 years ago

Read 2 more answers

Match the parametric equations with the verbal descriptions of the surfaces by putting the letter of the verbal description to t

alukav5142 [94]

Answer:

1. B

2. C

3. A

4. D

Step-by-step explanation:

The parametric equations of the circular cylinder are:

$x(u,v)=a\cos v\\y(u,v)=a\sin v\\z(u,v)=u$

If the orientation of the cylinder is changed to have the height $u$ along the x-axis, the parametric equations of the cylinder match:

$3. \mathbf{r} \left( u, v \right) = u \mathbf{i} + \cos v \mathbf{j} + \sin v \mathbf{k}$

The parametric equations of the circular paraboloid are:

$x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=u^2$

Using the units vectors the parametric equations match:

$1. \mathbf{r} \left( u, v \right) = u \cos v \mathbf{i} + u \sin v \mathbf{j} + u^{2} \mathbf{k}$

The parametric equations of the cone are:

$x(u,v)=au\cos v\\y(u,v)=au\sin v\\z(u,v)=u$

Using the units vectors and rotating the base of the cone from $z=0$ to $x=0$ the parametric equations match:

$2. \mathbf{r} \left( u, v \right) = u \mathbf{i} + u \cos v \mathbf{j} + u \sin v \mathbf{k}$

The equation left is the equation of a plane:

$4. \mathbf{r} \left( u, v \right) = u \mathbf{i} + v \mathbf{j} + \left( 2u - 3v \right) \mathbf{k}$

5 0

4 years ago

1. b+4= 2.4 2. 3.6 = 1.2g 3. 3.75x = 3 4. w-9 = -4.1 5. -7.4 = 8.8 + p 6. 2.9 = y - 6.3 7. A+5.7 = 1.5 8. -3.5 = V/0.2 9. Z/9 =

Marrrta [24]

1. b=2.4-4
b= -1.6

2. 1.2g/1.2 = 3.6/1.2
g=3

3. 3.75x/3.75 = 3/3.75
x= 0.8

4. w = -4.1 + 9
w= 4.9

5. p = -7.4 - 8.8
p= -16.2

6. y = 2.9 + 6.9
y = 9.8

7. A= 1.5 - 5.7
A= -4.2

8. V/0.2 * 0.2 = -3.5 * 0.2
V= -0.7

9. Z/9 * 9 = 1.6 * 9
Z= 14.4

10. -9.9t/-9.9 = -9.9/-9.9
t= 1

7 0

3 years ago

Read 2 more answers