Hi there!
The range of a function describes its possible y-values. For example, y=x produces a linear graph. Its range is all real numbers, meaning that for any value of y, the function is defined.
However, for y=x², for example, the range is y>0, since there the graph doesn't travel to y-values less than 0. The function is only defined when y>0.
To find the range of the given functions, you can try graphing them. Or, if you've memorized the ranges of their parent functions, you can try to take that and apply transformations.
Answer for the first question:
f(x)=-√x
The parent function is f(x)=√x. The range of this is y≥0.
f(x)=-√x
Adding a negative in front of the square root reflects the function across the x-axis, meaning the range is therefore flipped too:
y≤0
I hope this helps!
Answer:
dsasdasedssdafs
Step-by-step explanation:
dsadasdsaddsadad
Answer:
h = 3
Step-by-step explanation:
Dividing by a fraction is the same as multiplying by its reciprocal.
So h / (1/2) is the same as h * 2 or 2h
2h = 6
Divide both sides by 2 to isolate the variable h.
2h/2 = 6/2
h = 6/2
h = 3
Since it is a perfect square trinomial, it is of the form:
a^2x^2-2abx+b^2 which simplifies to (ax-b)^2
Therefore:
sqrt(a)=sqrt(25)=5
sqrt(b)=sqrt(36)=6
Plug in a and b:
(ax-b)^2
(5x-6)^2
Test to make sure it did fit the formula:
-2abx=-60 (where x is 1)
-2(5)(6)=-60
-2(30)=-60
-60=-60
Answer:
(5x-6)^2
30.
If 180 time six is 1080 and 1080 times six equals 6480
