All categories

3 years ago

I need help fast

Mathematics

1 answer:

Anni [7]3 years ago

6 0

Answer:

2.83 units diagonally

2 units horizontally and 2 units vertically

Step-by-step explanation:

x position difference -2-(-4)=2

y position difference 7-5=2

2 units horizontally and 2 units vertically on a graph

2^2+2^2=8

sq rt 8=2.83 units

You might be interested in

Which graph represents -5x + 3y > 9?

Ann [662]

Answer:

y>3+5x/3

Step-by-step explanation:

4 0

3 years ago

Solve (x + 3)2 + (x + 3) – 2 = 0. Let u = Rewrite the equation in terms of u. (u2 + 3) + u – 2 = 0 u2 + u – 2 = 0 (u2 + 9) + u –

Verdich [7]

Answer:

The solutions of the original equation are x=-5 and x=-2

Step-by-step explanation:

we have

$(x+3)^2+(x+3)-2=0$

Let

$u=(x+3)$

Rewrite the equation

$(u)^2+(u)-2=0$

Complete the square

$u^2+u=2$

$u^2+u+1/4=2+1/4$

$u^2+u+1/4=9/4$

rewrite as perfect squares

$(u+1/2)^2=9/4$

square root both sides

$(u+1/2)=\pm\frac{3}{2}$

$u=(-1/2)\pm\frac{3}{2}$

$u=(-1/2)+\frac{3}{2}=1$

$u=(-1/2)-\frac{3}{2}=-2$

the solutions are

u=-2,u=1

Alternative Method

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$(u)^2+(u)-2=0$

$a=1\\b=1\\c=-2$

substitute in the formula

$u=\frac{-1\pm\sqrt{1^{2}-4(1)(-2)}} {2(1)}$

$u=\frac{-1\pm\sqrt{9}} {2}$

$u=\frac{-1\pm3} {2}$

$u=\frac{-1+3} {2}=1$

$u=\frac{-1-3} {2}=-2$

the solutions are

u=-2,u=1

Find the solutions of the original equation

For u=-2

$-2=(x+3)$ ----> $x=-2-3=-5$

For u=1

$1=(x+3)$ ----> $x=1-3=-2$

therefore

The solutions of the original equation are

x=-5 and x=-2

4 0

3 years ago

Read 2 more answers

Find the distance between the pair of points. E(7-2), F(-2,10) d=

murzikaleks [220]

The answer is 15.
Using the distance formula you’d get. Sqrt(-2-7)^2+(-10-2)^2

Sqrt(-9)^2+(-12)^2

Sqrt(81+144)

Sqrt(225)

D=15

7 0

2 years ago

Look at this set of 8 numbers:33769234 how would the range change if the number 6 replaced the number 7 in the set

klio [65]

Put the numbers in order

2,3,3,3,4,6,7,9.....the range is the largest number minus the smallest number
so as it is, the range is (9 - 2) = 7

if u replaced the 7 with a 6...
2,3,3,3,4,6,6,9...the range is STILL (9 - 2) = 7

3 0

2 years ago

The longer leg of a right triangle is 4 more than the short leg. The hypotenuse is eight less than the sum of the 2 legs.

Crazy boy [7]

Answer:

SteLet a = short leg of the right triangle, b = the longer leg, and c = the hypotenuse.

The longer leg of a right triangle is 4inches longer than the shorter leg: b = a + 4

The hypotenuse is 8inches longer than the shorter leg: c = a + 8

Use the Pythagorean Theorem:

a2 + b2 = c2

a2 + (a+4)2 = (a+8)2

a2 + a2 + 8a + 16 = a2 + 16a + 64

a2 - 8a - 48 = 0

Factors to:

(a-12)(a+4) = 0

a = 12, -4

Since we can't have a side of -4, a = 12

Shorter Leg = 12 inches

Longer Leg = 12 + 4 = 16 inches

Hypotenuse = 12 + 8 = 20 inches

6 0

3 years ago