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3 years ago

Find the area. WILL MARK BRAINLIEST

Mathematics

2 answers:

Kay [80]3 years ago

7 0

Answer:

The area would be 108 mm.

Step-by-step explanation:

First I found the area of the whole shape, then I subtracted the area of the unshaded part. from the shaded part.

KengaRu [80]3 years ago

6 0

Answer:

Step-by-step explanation:

1.Area of a triangle is 1/2bh

b=18 h=13

1/2*18*13=9*13=117 cm²

2. b=3+4=7 h=4

1/2(7*4)=1/2*28=14 cm²

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2 years ago

The table shows a proportional relationship between the number of pounds of grapes

WINSTONCH [101]

Answer:

Pounds of grapes: 8; total cost: $5.52

Step-by-step explanation:

Find the proportional relationship for 1. 1:0.69
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2 years ago

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2 years ago

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What is the value of the discriminant for the quadratic equation –3 = –x^2 + 2x?

ANTONII [103]

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3 years ago

Can someone please help me with my Question #29 of The Quadratic Relations for me please?

lara [203]

Answer:

Calculate the first differences between the y-values:

$\sf 3 \underset{+1}{\longrightarrow} 4 \underset{+3}{\longrightarrow} 7 \underset{+5}{\longrightarrow} 12 \underset{+7}{\longrightarrow} 19$

As the first differences are not the same, we need to calculate the second differences:

$\sf 1 \underset{+2}{\longrightarrow} 3 \underset{+2}{\longrightarrow} 5 \underset{+2}{\longrightarrow} 7$

As the second differences are the same, the relationship between the variable is quadratic and will contain an $x^2$ term.

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To determine the quadratic equation

The coefficient of $x^2$ is always half of the second difference.

As the second difference is 2, and half of 2 is 1, the coefficient of $x^2$ is 1.

The standard form of a quadratic equation is: $y=ax^2+bx+c$

(where a, b and c are constants to be found).

We have already determined that the coefficient of $x^2$ is 1.

Therefore, a = 1

From the given table, when $x=0$ , $y=12$ .

$\implies a(0)^2+b(0)+c=12$

$\implies c=12$

Finally, to find b, substitute the found values of a and c into the equation, then substitute one of the ordered pairs from the given table:

$\begin{aligned}\implies x^2+bx+12 & = y\\ \textsf{at }(1,19) \implies (1)^2+b(1)+12 & = 19\\ 1+b+12 & = 19\\b+13 & =19\\b&=6\end{aligned}$

Therefore, the quadratic equation for the given ordered pairs is:

$y=x^2+6x+12$

7 0

2 years ago